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What volume of 5 percent aluminum acetate solution will be needed if 120 ml of 0.05 percent solution is extemporaneously compounded for patient use?
To calculate the volume needed, you can use the formula C1V1 = C2V2, where C1 is the concentration of the initial solution, V1 is the initial volume, C2 is the concentration of the final solution, and V2 is the final volume. Plugging in the values, you get (0.05)(120) = (5)(V2), which simplifies to V2 = 1.2 ml. Therefore, 1.2 ml of the 5% aluminum acetate solution will be needed.
How do make a percent sucrose solution?
To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).
How do you prepare 6n ammonium hydroxide from 30 percent solution?
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
How much calcium hypochlorite powder at 65 percent strength is needed to make 200 liters of 2 percent hypochlorite solution?
You would need 6.15 kg of calcium hypochlorite powder at 65% strength to make 200 liters of 2% hypochlorite solution.
What mass of water must be added to 255.0g NaCl to make a 15.00 percent by mass aqueous solution?
To make a 15.00% by mass aqueous solution with NaCl, the mass of NaCl is 255.0g. This means that 15.00g of NaCl is present in every 100.00g of solution. To find the mass of water needed, first calculate the mass of NaCl in the final solution, then subtract this amount from the total mass of the solution (water + NaCl).
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 5?
50liters
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the second 30 percent solution is needed to make a 400 L solution that is 62 percent acid?
144liters
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated. How much of the first 60 percent is needed to make a 100 L solution that's 50 percent?
50
A chemist has one solution that is 60 percent chlorinated and another that is 40 percent chlorinated How much of each solution is needed to make a 100 liter solution that is 50 percent chlorinated?
50 Liters of the 60% solution.
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 50?
To create a 50% chlorinated solution from the 60% and 40% solutions, the chemist will need to mix the two in equal amounts. Therefore, 50 L of the 60% solution and 50 L of the 40% solution are needed to make a 100 L solution that is 50% chlorinated.
When A chemist has one solution that is 80 acid and another solution that is 30 acid. How much of the first (80) solution is needed to make a 400 L solution that is 62 acid?
You need 256 litres.
How many liters of 93 percent acid solution are needed to make a 9 percent solution with 50 liters of water?
4.84
Jerry is experimenting with chemicals in the laboratory He mixes a solution that is 10 percent acid with a solution that is 30 percent acid How much of the 10 percent acid solution will be needed to m?
10 liters
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid how much of the second 30 percent solution is needed to make a 400L that is 62 percent acid?
.80x+.30y=400*.62 .80x+.30y=248 This is equation one. x+y=400 x=400-y This is the second equation. .80(400-y)+.30y=248 320-.80y+.30y=248 -.50y=-72 Y=144 X=256 CHECK .80(256)+.30(144)=400(.62) 204.8+43.2=248 248=248
How much of a 4 percent solution is needed for a 100mg dose?
2.5ml
Mary is experimenting with chemicals in the laboratory She mixes a solution that is 10 percent acid with a solution that is 25 percent acid How much of the 10 percent acid solution will be needed to m?
16 2/3 liters
How many liters of 9 percent salt solution and 18 percent salt solution are needed to make 18 liters of 10 percent salt solution?
A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent
