Add 200 grams of the salt to 800 g of water, mix and dissolve, and you've got your desired 20% solution.
Type your answer here... weight out 0.85g of sodium chloride and dissolve in 1L of water.
NOT: 15 ounces to make 10%Correct answer:Twenty ouncesCalculus:Let it be M ounces. Then:20%*(M ounce) + 5%*(40 ounce) = 10%*(M+40 ounce)20*M + 200 = 10*M + 400(20-10)*M = 400-20010M = 200M = 20
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
it dies since it enters a hypotonic solution thus making it shrink
Yes this saline is a hypertonic solution but 3% saline is also not normal. There is nothing "normal" about it. There is only one "normal saline" and that is 0.9%.
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
10
98 mL
20 volume is 6% solution. To make it 3% solution just add same volume of water to the original 6% solution and you have double volume of 3% solution.
20%
222.223 ml @ 20% solution = 44.444 ml 277.777 ml @ 65% solution = 180.555 ml total = 225 ml out of 500 ml = 45%
The mole fraction of HCl in 20 percent aqueous solution is 0.21.
Add an 0.4 L of solvent to 0.6 L solvent: 50% * 0.4 L = 20% * (0.4 +0.6) L