You can't unless something is missing in your question.
Yes, you can do 12 + 7 + 5 = 24
No. You need at least four.
The numbers are 746, 747 and 748, as well as 745, 747 and 749 using only consecutive odd whole numbers.
61
Because of the question's ambiguity, it is hard to tell exactly what is meant. However, to cover all possibilities:If there are four numbers and each is used once, there are 4! = 4 x 3 x 2 x 1 = 24 different combinations.If there are the 10 digits used to make a four-digit number, using each once, we have 10!/(10-4)! = 10!/6! = 10 x 9 x 8 x 7 = 5040 different combinations.Or does he mean this?Using the binary numbering system.Binary Decimal0000 00001 10010 20011 30100 40101 50110 60111 71000 81001 91010 101011 111100 121101 131110 141111 15
how do i make 17 using only 2 4 6 8
Using only sums and differences, and not necessarily all four numbers, 1, 3, 9 and 27 will make all numbers from 0 to 40.
Google "Four Fours" and you will find a number of solutions, presented more comprehensively than we can.
[(-2) + (-1)]/(-3) * [(-7) - (-5)]
7 and 9 is 16. 16x2 is 32. 32-8 is 24.
Yes
9
1
Yes we can make it.
75 - 32
if your using whole numbers, u can only use 3
Not possible