Use equimolar quantities:
LiOH + HC2H3O2 (acetic acid) --> C2H3O2- (acetate) + Li+ + H2O
This equation is:HBr + LiOH = LiBr + H2O
Lithium atom become the cation Li+.
There is only one equivalent of OH^-1 in one molecule of HC2H3O2.
To find the mass of the solute in a 500 mL solution of 2.98 M lithium hydroxide (LiOH), you first need to calculate the number of moles of LiOH. The molarity (M) is defined as moles of solute per liter of solution, so 2.98 M means there are 2.98 moles of LiOH in 1 liter. For 500 mL (0.5 L), the moles of LiOH would be 2.98 moles/L × 0.5 L = 1.49 moles. Finally, the molar mass of LiOH is approximately 23.94 g/mol, so the mass of the solute is 1.49 moles × 23.94 g/mol ≈ 35.63 grams.
Melting:462 C Boiling: 924 C decomp.
I believe it is already balanced. No coefficients neccessary
The chemical equation for the reaction between hydrochloric acid (HCl) and lithium hydroxide (LiOH) is: HCl + LiOH -> LiCl + H2O This reaction produces lithium chloride (LiCl) as a salt and water (H2O) as a product.
liho+h2s=
It's a chemical reaction.
LiOH
lithium, hydrogen, oxygen
This is a double displacement reaction, where the sodium (Na) ion in NaHCO3 switches places with the hydrogen (H) ion in HC2H3O2 to form NaC2H3O2 and H2CO3.
LiOH + HCl -> LiCl + H2O This is an acid base neutralization reaction producing a salt, lithium chloride (LiCl ) and water.
The chemical reaction is:Li2CO3 + Ca(OH)2 = 2 LiOH + CaCO3Molar maass of LiOH is 23,95 g; molar mass of calcium hydroxide is 74,093 g.74,093 g Ca(OH)2----------------2.23,95 g LiOH25 g Ca(OH)2----------------------xx = (25 x 2 x 23,95)/74,093 = 16,2 g LiOH
The conjugate acid of LiOH is considered Li+.
The conjugate base of HC2H3O2 is C2H3O2-. This ion is formed when HC2H3O2 donates a proton.
This equation is:HBr + LiOH = LiBr + H2O