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To find the mass of the solute in a 500 mL solution of 2.98 M lithium hydroxide (LiOH), you first need to calculate the number of moles of LiOH. The molarity (M) is defined as moles of solute per liter of solution, so 2.98 M means there are 2.98 moles of LiOH in 1 liter. For 500 mL (0.5 L), the moles of LiOH would be 2.98 moles/L × 0.5 L = 1.49 moles. Finally, the molar mass of LiOH is approximately 23.94 g/mol, so the mass of the solute is 1.49 moles × 23.94 g/mol ≈ 35.63 grams.

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