To find the mass of the solute in a 500 mL solution of 2.98 M lithium hydroxide (LiOH), you first need to calculate the number of moles of LiOH. The molarity (M) is defined as moles of solute per liter of solution, so 2.98 M means there are 2.98 moles of LiOH in 1 liter. For 500 mL (0.5 L), the moles of LiOH would be 2.98 moles/L × 0.5 L = 1.49 moles. Finally, the molar mass of LiOH is approximately 23.94 g/mol, so the mass of the solute is 1.49 moles × 23.94 g/mol ≈ 35.63 grams.
To find the mass of the solute (lithium sulfide) in 750mL of 0.188M solution, you need to multiply the volume of the solution (750mL) by the molarity (0.188 mol/L) and the molar mass of lithium sulfide (Li2S). First, calculate the number of moles in 750mL of 0.188M solution, then convert moles to grams using the molar mass of Li2S (45.88 g/mol).
Yes, this is exactly it. If you don't have a litre, it is still a certain molarity solution, provided you know the amount of moles. For example. 2 moles in 500ml. If there are 2 moles in every 500ml, there will be 4 moles in every 1000ml, i.e. 4 molar.
The atomic number of lithium is 3. The only stable isotope of lithium has 4 neutrons. Therefore its relative atomic mass is 7.
Naturally occurring lithium contains two isotopes. The common one has an atomic mass of 7. About one per cent of the lithium has an atomic mass of 6.The atomic mass of Lithium-Li is 6.941 grams.
The mass of lithium oxide (Li2O) is 8,o9 g.
Lithium hydroxide (LiOH) has formula mass 23.95 g/mol (anhydrous) or41.96 g/mol (monohydrate, LiOH.H2O) g/mol
To find the mass of the solute (lithium sulfide) in 750mL of 0.188M solution, you need to multiply the volume of the solution (750mL) by the molarity (0.188 mol/L) and the molar mass of lithium sulfide (Li2S). First, calculate the number of moles in 750mL of 0.188M solution, then convert moles to grams using the molar mass of Li2S (45.88 g/mol).
Yes, this is exactly it. If you don't have a litre, it is still a certain molarity solution, provided you know the amount of moles. For example. 2 moles in 500ml. If there are 2 moles in every 500ml, there will be 4 moles in every 1000ml, i.e. 4 molar.
1 mol of lithium hydroxide can absorb 1 mol of carbon dioxide. The molar mass of lithium hydroxide (LiOH) is 23.95 + 15.999 + 1.008 = 40.967 g/mol. The molar mass of carbon dioxide (CO2) is 12.011 + (2 x 15.999) = 44.011 g/mol. Therefore, 1.00 kg of lithium hydroxide can absorb 1000 g / 40.967 g/mol = 24.41 mol of CO2, which is 24.41 mol x 44.011 g/mol = 1073.1 g or 1.07 kg of gaseous carbon dioxide.
To determine the grams of lithium hydroxide present, you need to use its molar mass. The molar mass of LiOH is approximately 23.95 g/mol. Therefore, 3 moles of LiOH would be: 3 moles x 23.95 g/mol = 71.85 grams of lithium hydroxide.
To find the volume of 2.26M potassium hydroxide solution that contains 8.42g of solute, you can use the formula: moles = mass / molar mass. First, calculate the moles of solute using the given mass and molar mass of potassium hydroxide. Then, use the molarity (2.26M) to find the volume of the solution using the formula: volume = moles / molarity.
The solute is the material you're dissolving into your solution; in this case the ammonium chloride. 0.341 M (molar) means you need 0.341 mol/L.500mL = 0.5L, so to make 500 mL of solution you actually need 0.5*0.341 = 0.1705 moles of ammonium chloride.ammonium chloride weighs 53.491 g/mol (14.0067+1.00794+35.453, all the molecular weights of the elements in NH4Cl)0.1705*53.491 = 9.12 grams
You think probable to lithium.
First, calculate the mass of the solvent (water) using the total mass of the solution. Mass of solvent = Total mass of solution - Mass of solute. Then, convert the mass of the solute into moles using its molar mass. Finally, calculate the molar mass of the solute using the moles of solute and the mass of the solute. molar mass = Mass of solute (g) / Moles of solute.
Lithium's mass number is 6.941.
M=#mol solute / Liter of solution #mol solute= mass / molar mass #mol solute= 100 / 87 = 1.15 4= 1.15 / L solution 1.15 / 4 = 0.28 _____________________________________________________________ Since we were only given the (M) and grams of LiBr we had to find the mol of solute. To find the #mol of solute we divided the grams (which were given) over the molar mass of LiBr (87). We then got 1.15 . Now we are able to find the Liter of solution . First we plugged in our given values M= 4 & #mol solute= 1.15 . To find liter of solution we simply dived 1.15 over 4 which equals 0.28. --------------- I suppose that lithium bromide is not so soluble to prepare 4 M solutions in water at 20 0C.
Lithium is element #3. That, of course, is the atomic number - the number of protons. The atomic mass will of course depend on the specific isotope. The most common isotope is Lithium-7, that is, atomic mass = 7. Lithium-6 also occurs in nature as a stable isotope.