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What is the mass of the solute in 500mL of 0.341M ammonium chloride?
Wiki User
∙ 11y ago
The solute is the material you're dissolving into your solution; in this case the ammonium chloride. 0.341 M (molar) means you need 0.341 mol/L.
500mL = 0.5L, so to make 500 mL of solution you actually need 0.5*0.341 = 0.1705 moles of ammonium chloride.
ammonium chloride weighs 53.491 g/mol (14.0067+1.00794+35.453, all the molecular weights of the elements in NH4Cl)
0.1705*53.491 = 9.12 grams
Wiki User
∙ 11y ago
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