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How many grams of nacl would you dissolve in water to make a 50mM nacl solution with a 500mL of final volume?
Solubility increases with temperature, but the solubility of sodium chloride in water is 316 grams per litre at 0 degrees Celsius, and 330 grams per litre at 70 degrees Celsius. Since room temperature is somewhere between these two, this gives upper and lower limits of the solubility at room temperature.
50 grams of water has a volume of 50 cubic centimetres, or 0.05 litres. In one litre you could dissolve between 316 grams and 330 grams, so in 0.05 litres you could dissolve between 15.8 and 16.5 grams, where 15.8 = 316 x 0.05 and 16.5 = 330 x 0.05.
So we can say it's around 16 grams of NaCl in 50 grams of water at room temperature.
What else can I help you with?
How do you prepare a 500mL of 1M of NaCl solutuion?
If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl. However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g. So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL. You now have 100mL of a 5M NaCl solution.
How many grams of NaCl molecular weight 58.5 g mole -1 would you dissolve in water to make a 0.5M NaCl solution with 500 ml final volume?
You would need to dissolve 14.62 grams of NaCl in water to make a 0.5M NaCl solution with a final volume of 500 ml. This calculation is based on the formula: moles = Molarity x Volume (in liters), and then converting moles to grams using the molecular weight of NaCl.
How many grams of sodium chloride molecular weight 58.5 g mole would you dissolve in water to make a 5 solution with 500 final volume?
To make a 5% (w/v) solution, you would dissolve 25 grams of sodium chloride (5% of 500 grams) in water to make a final volume of 500 mL. Sodium chloride has a molecular weight of 58.5 g/mol.
How many grams of NaCl would be required to make 6M solution?
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
How much water would you need to add to 500ml of a 2.4m kcl solution to make a 1.0 m solution?
A 3 Molar solution has 3 moles of reagent per liter. 500mL of that solution has 1.5 moles of reagent. So to create a 2 moles per liter solution with 1.5 M or reagent, you will need a volume of 750 mL. So you will need to add 250 mL of water.
How will you prepare 500ml of 1N KOH solution?
To prepare 500mL of 1N KOH solution, you will need to dissolve 20 grams of KOH (potassium hydroxide) in enough water to make a final volume of 500mL. The molarity of the solution will be 1N, meaning it will contain 1 mole of KOH per liter of solution. Remember to wear appropriate safety gear such as gloves and goggles when working with chemicals.
How would you make a 500 ml solution of 1.0 M KCl?
To make a 1.0 M solution of KCl in 500 ml, you would need to weigh out 74.55 g of KCl (molar mass of KCl is 74.55 g/mol) and dissolve it in enough water to make a final volume of 500 ml. Remember to use a volumetric flask to accurately measure the final volume.
How do you prepare a 500mL of 1M of NaCl solutuion?
If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl. However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g. So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL. You now have 100mL of a 5M NaCl solution.
How many grams of NaCl molecular weight 58.5 g mole -1 would you dissolve in water to make a 0.5M NaCl solution with 500 ml final volume?
You would need to dissolve 14.62 grams of NaCl in water to make a 0.5M NaCl solution with a final volume of 500 ml. This calculation is based on the formula: moles = Molarity x Volume (in liters), and then converting moles to grams using the molecular weight of NaCl.
How many grams of calcium chloride would you dissolve in water to make a 0.2 M CaCl2 solution with 200 ml final volume?
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
How do you prepare 1 molar iodoacetamide solution?
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
How many grams of sodium chloride molecular weight 58.5 g mole would you dissolve in water to make a 5 solution with 500 final volume?
To make a 5% (w/v) solution, you would dissolve 25 grams of sodium chloride (5% of 500 grams) in water to make a final volume of 500 mL. Sodium chloride has a molecular weight of 58.5 g/mol.
What is the final concentration of a solution prepared by diluting of HCl to a final volume of?
To find the final concentration of a solution after dilution, you can use the formula: (C_1V_1 = C_2V_2), where (C_1) is the initial concentration, (V_1) is the initial volume, (C_2) is the final concentration, and (V_2) is the final volume. Plug in the values for the initial concentration, volume, and final volume to calculate the final concentration of HCl.
What is the molarity of a solution that is made using 1.2 moles of a substance in 500mL?
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
How do you make 0.25N K2CrO4 solution?
To make a 0.25N K2CrO4 solution, you need to first calculate the molecular weight of K2CrO4 (potassium chromate). Then, determine the grams of K2CrO4 needed to make the desired volume of solution at a concentration of 0.25N. Dissolve this amount of K2CrO4 in the required volume of solvent, usually water, to make the final solution.
How do you prepare 10mM ferric chloride solution?
To prepare a 10mM ferric chloride solution, first calculate the molecular weight of FeCl3 to determine the amount needed to achieve a concentration of 10mM. Dissolve this amount in a known volume of water or solvent to make up the final volume of the solution, ensuring thorough mixing to achieve homogeneity.
How would you prepare 500 mL of a 1M solution of acetic acid -HC2H3O2- from a stock solution of 6M of acetic acid?
You would need to dilute the 6M acetic acid solution by adding the appropriate volume of water. To prepare 500 mL of 1M solution, you would need to take (1/6)th of the volume of the 6M solution, which is (1/6) x 500 mL = 83.33 mL of the 6M solution. Dilute this with water to reach a final volume of 500 mL.
