To make a 0.25N K2CrO4 solution, you need to first calculate the molecular weight of K2CrO4 (potassium chromate). Then, determine the grams of K2CrO4 needed to make the desired volume of solution at a concentration of 0.25N. Dissolve this amount of K2CrO4 in the required volume of solvent, usually water, to make the final solution.
The molar mass of K2CrO4 is 294.18 g/mol. Therefore, the number of moles of K2CrO4 in 414.4 mg is 0.00141 mol. As there are 2 moles of chromium in 1 mole of K2CrO4, the number of moles of chromium is 0.00282 mol. The concentration of chromium in the stock solution is 28,200 ppm.
A chemical substance that will form a precipitate with NH4Cl solution is AgNO3, resulting in the formation of a white precipitate of AgCl. With K2CrO4 solution, Pb(NO3)2 will form a yellow precipitate of PbCrO4.
The white precipitate formed in the reaction between BaCl2 and K2CrO4 is BaCrO4 (barium chromate). This precipitate forms because Ba2+ ions from BaCl2 react with CrO4^2- ions from K2CrO4 to produce an insoluble compound that falls out of solution.
The chemical formula for potassium chromate is K2CrO4.
The dissociation equation for potassium chromate (K2CrO4) in water is: K2CrO4(s) -> 2K+(aq) + CrO4^2-(aq).
The molar mass of K2CrO4 is 294.18 g/mol. Therefore, the number of moles of K2CrO4 in 414.4 mg is 0.00141 mol. As there are 2 moles of chromium in 1 mole of K2CrO4, the number of moles of chromium is 0.00282 mol. The concentration of chromium in the stock solution is 28,200 ppm.
A chemical substance that will form a precipitate with NH4Cl solution is AgNO3, resulting in the formation of a white precipitate of AgCl. With K2CrO4 solution, Pb(NO3)2 will form a yellow precipitate of PbCrO4.
K2CrO4 Molarity (concentration) = moles of solute/Liters of solution (100 ml = 0.100 Liters ) Find moles K2CrO4 first. 3.50 grams = (1 mole K2CrO4/194.2 grams) = 0.01802 moles K2CrO4 ----------------------------------------------next Molarity = 0.01802 moles K2CrO4/0.100 Liters = 0.180 M K2CrO4 -------------------------
The white precipitate formed in the reaction between BaCl2 and K2CrO4 is BaCrO4 (barium chromate). This precipitate forms because Ba2+ ions from BaCl2 react with CrO4^2- ions from K2CrO4 to produce an insoluble compound that falls out of solution.
The chemical formula for potassium chromate is K2CrO4.
The dissociation equation for potassium chromate (K2CrO4) in water is: K2CrO4(s) -> 2K+(aq) + CrO4^2-(aq).
KCrO4 does not exist it is K2CrO4 and is called Potassium Chromate. Potassium dichromate is K2Cr2O7
K2CrO4 is a salt of a strong base (potassium hydroxide) and a weak acid (chromic acid). It is considered a basic salt because it contains an anion derived from a weak acid, which can accept a proton and act as a base in a solution.
Potassium chromate (K2CrO4) is a yellow colored compound.
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
When sulfuric acid (H2SO4) is added to a potassium chromate (K2CrO4) solution, the orange-yellow color of the chromate ions will change to red, due to the formation of chromium ions in the +6 oxidation state (CrO4^2- --> Cr2O7^2-).
The ion for K2CrO4 is the chromate ion, which has a chemical formula of CrO4^2-.