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A 3 Molar solution has 3 moles of reagent per liter. 500mL of that solution has 1.5 moles of reagent. So to create a 2 moles per liter solution with 1.5 M or reagent, you will need a volume of 750 mL. So you will need to add 250 mL of water.

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11y ago
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12y ago

m1v1 = m2v2

m1 is the 2.4M that was given.

v1 is 500ml which was also given.

m2 is 1.0M that was given.

we need to solve for v2

v2 is the amount of solution (500mL) plus the amount of water we need to add (v)

our equation looks like this:

(2.4)(500) = (1)(v + 500)

simplify both sides

1200 = v + 500

v = 700

700mL of water is added

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11y ago

In order to make a 2 M solution from a 5 M solution, the volume of the original solution must be increase by a factor of 5/2. Therefore, the volume of the new solution must be 2(5/2) or 5 liters, requiring about 3 liters of additional water. This is not necessarily achieved by adding 3 liters of pure water, however, because the density of the two solutions may be different from one another and from that of pure water.

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Q: How much water would you need to add to 500ml of a 2.4m kcl solution to make a 1.0 m solution?
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