0
M=#mol solute / Liter of solution
#mol solute= mass / molar mass
#mol solute= 100 / 87 = 1.15
4= 1.15 / L solution
1.15 / 4 = 0.28
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Since we were only given the (M) and grams of LiBr we had to find the mol of solute. To find the #mol of solute we divided the grams (which were given) over the molar mass of LiBr (87). We then got 1.15 . Now we are able to find the Liter of solution . First we plugged in our given values M= 4 & #mol solute= 1.15 . To find liter of solution we simply dived 1.15 over 4 which equals 0.28.
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I suppose that lithium bromide is not so soluble to prepare 4 M solutions in water at 20 0C.
What else can I help you with?
What volume of 0.256 M sodium bromide contains 18.7 grams of bromide?
Need moles sodium bromide first. 18.7 grams NaBr (1 mole NaBr/102.89 grams) = 0.1817 moles NaBr =====================Now, Molarity = moles of solute/Liters of solution 0.256 M NaBr = 0.1817 moles NaBr/X Liters Liters = 0.1817/0.256 = 0.7098 Liters -------------------------( you do sigi figis )
Molarity of 734 grams of lithium sulfate are dissolved to make 2500ml of solution?
To find the molarity of the solution, first calculate the number of moles of lithium sulfate in 734g. Then, divide the moles by the volume of solution in liters to get the molarity. Remember to convert grams to moles using the molar mass of lithium sulfate (Li2SO4).
The formula for lithium bromide is?
The formula for lithium bromide is LiBr. The compound has a molar mass of 86.845 grams per mole. One of its main uses is as a desiccant.
What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium flouride?
The molarity of the solution can be calculated by first finding the moles of lithium fluoride using its molar mass, which is 25.94 g/mol for lithium and 19.00 g/mol for fluorine. Add these together to find the molar mass of lithium fluoride. Then, divide the mass of lithium fluoride by its molar mass to get the moles. Finally, divide the moles by the volume of the solution in liters to get the molarity.
How much potassium bromide in grams should be added to water to prepare 0.50L of solution with a molarity of 0.125M?
To calculate the amount of potassium bromide needed, use the formula: moles = molarity x volume (in liters). First, convert the volume to liters by dividing 0.50L by 1000. Then, multiply the molarity (0.125M) by the volume in liters to find the moles of potassium bromide needed. Finally, convert moles to grams using the molar mass of potassium bromide (KBr).
How many grams of lithium bromide are present in 25.0 mL of a 0.100 M soution?
To calculate the grams of lithium bromide present in the solution, you would first determine the moles of lithium bromide using the formula: moles = Molarity x Volume (L). Once you have the moles, you can convert it to grams using the molar mass of lithium bromide (86.85 g/mol).
What volume of 0.256 M sodium bromide contains 18.7 grams of bromide?
Need moles sodium bromide first. 18.7 grams NaBr (1 mole NaBr/102.89 grams) = 0.1817 moles NaBr =====================Now, Molarity = moles of solute/Liters of solution 0.256 M NaBr = 0.1817 moles NaBr/X Liters Liters = 0.1817/0.256 = 0.7098 Liters -------------------------( you do sigi figis )
What is the molarity of a solution that contains 1.1 of lithium in 0.5 liters of solution?
If 1,1 is grams the molarity is 0,317.
Molarity of 734 grams of lithium sulfate are dissolved to make 2500ml of solution?
To find the molarity of the solution, first calculate the number of moles of lithium sulfate in 734g. Then, divide the moles by the volume of solution in liters to get the molarity. Remember to convert grams to moles using the molar mass of lithium sulfate (Li2SO4).
What volume of 0.256 M sodium bromide contains 18.7 grams of sodium bromide?
From the definition of molarity, one liter of the stated solution contains 0.256 mole of sodium bromide. The gram formula weight of sodium bromide is 102.89; therefore, one liter of the solution contains 0.256 X 102.89 or 26.34 grams. 18.7/26.34 = 0.710, the fraction of a liter that contains 18.7 grams of sodium bromide.
The formula for lithium bromide is?
The formula for lithium bromide is LiBr. The compound has a molar mass of 86.845 grams per mole. One of its main uses is as a desiccant.
What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium flouride?
The molarity of the solution can be calculated by first finding the moles of lithium fluoride using its molar mass, which is 25.94 g/mol for lithium and 19.00 g/mol for fluorine. Add these together to find the molar mass of lithium fluoride. Then, divide the mass of lithium fluoride by its molar mass to get the moles. Finally, divide the moles by the volume of the solution in liters to get the molarity.
How much potassium bromide in grams should be added to water to prepare 0.50L of solution with a molarity of 0.125M?
To calculate the amount of potassium bromide needed, use the formula: moles = molarity x volume (in liters). First, convert the volume to liters by dividing 0.50L by 1000. Then, multiply the molarity (0.125M) by the volume in liters to find the moles of potassium bromide needed. Finally, convert moles to grams using the molar mass of potassium bromide (KBr).
What is the Molarity of a substance that contains 4.13 grams of magnesium bromide in 845 liters of a solution?
Molarity= mols/ L So, take 4.13g MgBr2 ( because Mg has a +2 charge and Bromide has a +1 charge) and divide it by 184.1 g MgBr2 which gives you .022 mols of MgBr2 then you divide .022 by 845 which gives you 2.65 M Molarity = 2.65M
How many grams of a drug must be used to prepare 3 liters of a 2 percent solution?
To prepare a 2% solution in 3 liters, you would need 60 grams of the drug. This is calculated by multiplying the volume (3 liters) by the percentage (2%) and converting the result to grams. 3 liters x 2% = 60 grams.
How many grams of hcl are contained in 4 liters of a 12m solution?
438 grams.
What is the molarity of the solution obtained when 26.3 g of potassium bromide are diluted to 487 mL?
To find the molarity of the solution, first calculate the number of moles of potassium bromide using its molar mass. Then, divide the number of moles by the volume of the solution in liters (487 mL = 0.487 L) to get the molarity.
