438 grams.
To calculate the grams of solute in the solution, first convert ppm to g/L by multiplying by the density. The density of a SnCl2 solution is approximately 2.3 g/mL. Then, convert L to mL by multiplying by 1000. Finally, multiply the concentration in g/L by the volume in mL to find the total grams of SnCl2 in the solution.
To prepare a 2% solution in 3 liters, you would need 60 grams of the drug. This is calculated by multiplying the volume (3 liters) by the percentage (2%) and converting the result to grams. 3 liters x 2% = 60 grams.
There are 30 liters of hydrochloric acid in 300 liters of a solution that is 10% hydrochloric acid by volume.
88,218 liters.
897.5 centiliters are contained in 8.975 liters.
7.473 kiloliters are contained in 7473 liters.
0.03696 centiliters are contained in 0.0003696 liters.
0.123 liters are contained in 12.3 centiliters.
386.4 centiliters are contained in 3.864 liters.
109.31 liters are contained in 10,931 centiliters.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams