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How many grams of NaBr are contained in 75.0 mL of a 1.5 M NaBr solution?
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Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters )
Get moles NaBr
1.5 M NaBr = moles NaBr/0.075 Liters
= 0.1125 moles NaBr (102.89 grams/1 mole NaBr)
= 11.575 grams NaBr ( call it 12 grams )
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