Sodium and bromine are the elements in sodium bromide (NaBr) compound.
It is Sodium Bromide, which is a halide (group 7 elements), yes, it is a variation of salt in a compound.
A formula unit of NaBr contains 2 atoms: 1 sodium and 1 bromine.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
Sodium bromide is the ionic compound formed by the combination of sodium (Na) cation and bromide (Br) anion. It is a white crystalline solid that is commonly used in pharmaceuticals and photographic chemicals.
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
There are two elements that make up the compound NaBr, or sodium bromide. These two elements are sodium and bromine.
It is Sodium Bromide, which is a halide (group 7 elements), yes, it is a variation of salt in a compound.
A formula unit of NaBr contains 2 atoms: 1 sodium and 1 bromine.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
Following the definitiion of molarity, 1.90 M = (weight in g) / (102.894 * 0.105) So weight of NaBr = 1.90 * 102.894 * 0.105 = 20.53 g
The melting point of NaBr is 747 oC.
Sodium bromide is the ionic compound formed by the combination of sodium (Na) cation and bromide (Br) anion. It is a white crystalline solid that is commonly used in pharmaceuticals and photographic chemicals.
The chemical symbol for sodium bromide is NaBr.
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
No, NaBr is not an acid. It is the chemical formula for sodium bromide, which is a salt composed of sodium cations (Na+) and bromide anions (Br-).
2 Na + Br2 --> 2 NaBr
Na + Br ₂→ NaBr This happens because: When certain diatomic elements (Br, I, N, Cl, H, O, F) are alone you add a 2 as a subscript so they are (Br₂, I,₂ N₂, Cl₂, H₂, O₂, F₂). But when you cross Na (which has a charge of +1) with Br (which has a charge of -1) They cancel and you get NaBr. Na + Br ₂→ NaBr This happens because: When certain diatomic elements (Br, I, N, Cl, H, O, F) are alone you add a 2 as a subscript so they are (Br₂, I,₂ N₂, Cl₂, H₂, O₂, F₂). But when you cross Na (which has a charge of +1) with Br (which has a charge of -1) They cancel and you get NaBr.