A formula unit of NaBr contains 2 atoms: 1 sodium and 1 bromine.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
No, NaBr (sodium bromide) is an ionic compound, not a covalent compound. Ionic compounds are formed by the transfer of electrons between atoms of different electronegativities, resulting in a bond with a full transfer of electrons and an electrostatic attraction between oppositely charged ions.
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
No, NaBr is not an acid. It is the chemical formula for sodium bromide, which is a salt composed of sodium cations (Na+) and bromide anions (Br-).
If you think to a simple binary bromide as NaBr: 166,57.10e23 atoms.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
Following the definitiion of molarity, 1.90 M = (weight in g) / (102.894 * 0.105) So weight of NaBr = 1.90 * 102.894 * 0.105 = 20.53 g
No, NaBr (sodium bromide) is an ionic compound, not a covalent compound. Ionic compounds are formed by the transfer of electrons between atoms of different electronegativities, resulting in a bond with a full transfer of electrons and an electrostatic attraction between oppositely charged ions.
The melting point of NaBr is 747 oC.
The chemical symbol for sodium bromide is NaBr.
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
No, NaBr is not an acid. It is the chemical formula for sodium bromide, which is a salt composed of sodium cations (Na+) and bromide anions (Br-).
2 Na + Br2 --> 2 NaBr
The percent composition of bromine in NaBr is approximately 77.7%. This is calculated by dividing the molar mass of bromine by the molar mass of NaBr and then multiplying by 100.
To find the mass of NaBr in the mixture, we first calculate the mass of Na in NaCl and NaBr combined, which is 0.76 g. Since NaCl contains one Na atom and NaBr contains one Na atom, this entire mass comes from Na in NaCl and NaBr. Therefore, the mass of NaCl is 0.76 g and the remaining mass of the mixture (2.03 g - 0.76 g = 1.27 g) is due to NaBr.