A formula unit of NaBr contains 2 atoms: 1 sodium and 1 bromine.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
No, NaBr is a neutral salt.
NaBr is a salt.
Sodium bromide (NaBr) is a salt.
If you think to a simple binary bromide as NaBr: 166,57.10e23 atoms.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
No, NaBr is a neutral salt.
NaBr is a salt.
Following the definitiion of molarity, 1.90 M = (weight in g) / (102.894 * 0.105) So weight of NaBr = 1.90 * 102.894 * 0.105 = 20.53 g
Sodium bromide (NaBr) is a salt.
2 Na + Br2 --> 2 NaBr
NiCl2 + 2 NaBr-----------NiBr2 + 2 NaCl
NaBr is ionically bonded, the maximum possible degree of polarity.
NaBr is Sodium Bromide (Na is Sodium, Br is Bromine) Usually when you link only two elements together the ending of the product is -ide
Generally the ionic bond is formed between a metal and a nonmetal (cation and anion). As an example, sodium and bromine: sodium bromide, NaBr.