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How many grams of NaBr are contained in 75.0 mL of a 1.5 M NaBr solution?
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
What reactant is limiting if 3000 cm3 of Cl2 at STP react with a solution containing 25 grams of NaBr?
Cl2 + 2NaBr => Br2 + 2NaCl One mole Cl2 reacts with 2 moles NaBr Cl2 = 71 NaBr = 102.9 Molar volume = 22.414 L/mole for ideal gas @STP 3L Cl2 = 3/22.414 = 0.1338 mole 25g NaBr = 25/102.9 = 0.2430 mole 0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction The NaBr is the limiting reagent
How many elements NaBr?
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
Is nabr a acid?
No, NaBr is not an acid. It is the chemical formula for sodium bromide, which is a salt composed of sodium cations (Na+) and bromide anions (Br-).
Is NaBr a acid or base or salt?
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
How many grams of NaBr are contained in 75.0 mL of a 1.5 M NaBr solution?
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
What is the molar mass of NaBr?
Sodium bromide (NaBr) has a weight of 102.89 grams per mole. Determining the mass of NaBr in a mixture can be calculated if the constituent weights of all the others are known. The total masses of the knows can be subtracted by the overall weight to isolate the mass of NaBr.
Is sodium bromide an element compound or mixture?
Sodium bromide (NaBr) is a compound.
How many grams of NaBr are contained in 105ml of a 1.90M NaBr solution?
Following the definitiion of molarity, 1.90 M = (weight in g) / (102.894 * 0.105) So weight of NaBr = 1.90 * 102.894 * 0.105 = 20.53 g
What volume of 0.256 M sodium bromide contains 18.7 grams of bromide?
Need moles sodium bromide first. 18.7 grams NaBr (1 mole NaBr/102.89 grams) = 0.1817 moles NaBr =====================Now, Molarity = moles of solute/Liters of solution 0.256 M NaBr = 0.1817 moles NaBr/X Liters Liters = 0.1817/0.256 = 0.7098 Liters -------------------------( you do sigi figis )
What reactant is limiting if 3000 cm3 of Cl2 at STP react with a solution containing 25 grams of NaBr?
Cl2 + 2NaBr => Br2 + 2NaCl One mole Cl2 reacts with 2 moles NaBr Cl2 = 71 NaBr = 102.9 Molar volume = 22.414 L/mole for ideal gas @STP 3L Cl2 = 3/22.414 = 0.1338 mole 25g NaBr = 25/102.9 = 0.2430 mole 0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction The NaBr is the limiting reagent
What is the melting point of NaBr?
The melting point of NaBr is 747 oC.
How many elements NaBr?
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
What is the chemical symbol for sodium bromide?
The chemical symbol for sodium bromide is NaBr.
Is nabr a acid?
No, NaBr is not an acid. It is the chemical formula for sodium bromide, which is a salt composed of sodium cations (Na+) and bromide anions (Br-).
Is NaBr a acid or base or salt?
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
What is a balance chemical equation for the synthesis of NaBr from Na and Br2?
2 Na + Br2 --> 2 NaBr
