No, NaBr is a neutral salt.
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
NaBr is a salt composed of sodium cation Na+ and bromide anion Br-. It is formed from the neutralization reaction between a strong acid, such as hydrobromic acid (HBr), and a strong base, such as sodium hydroxide (NaOH). Therefore, NaBr is neutral and does not act as an acid or a base in solution.
No, HBr is an acid, LiOH and MgS are bases, and NaBr is a salt.
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
NaBr is a salt composed of sodium cation Na+ and bromide anion Br-. It is formed from the neutralization reaction between a strong acid, such as hydrobromic acid (HBr), and a strong base, such as sodium hydroxide (NaOH). Therefore, NaBr is neutral and does not act as an acid or a base in solution.
No, HBr is an acid, LiOH and MgS are bases, and NaBr is a salt.
Well, honey, technically speaking, a buffer is a solution that can resist changes in pH when small amounts of acid or base are added. So, if you mix hydrobromic acid (HBr) and sodium bromide (NaBr) together, you could potentially have a buffer solution if the concentrations are right. But hey, don't get too excited, it's not as simple as just throwing them together and calling it a day.
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
The melting point of NaBr is 747 oC.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
The chemical symbol for sodium bromide is NaBr.
Dilute Hydrobromic acid react with Sodium Thiosulfate to produce Sodium Bromide, Sulfur Dioxide, Sulfur and Water, according to the following equationNa2S2O3 +2 HBr ----> 2 NaBr + S + SO2+ H2O
The products of the reaction between hydrogen bromide (HBr) and sodium hydroxide (NaOH) are sodium bromide (NaBr) and water (H2O). This is a neutralization reaction where the acid (HBr) reacts with the base (NaOH) to form a salt (NaBr) and water.
Sodium Bromide is produced from the reaction of Hydrobromic acid and sodium hydroxide.