Dilute Hydrobromic acid react with Sodium Thiosulfate to produce Sodium Bromide, Sulfur Dioxide, Sulfur and Water, according to the following equation
Na2S2O3 +2 HBr ----> 2 NaBr + S + SO2+ H2O
Sodium Bromide is produced from the reaction of Hydrobromic acid and sodium hydroxide.
To determine the mass of HBr gas formed, you first need to find the limiting reactant. Once you determine that, you can calculate the amount of HBr produced using the stoichiometry of the reaction and then convert it to mass using the molar mass of HBr. Without the balanced chemical equation, it is not possible to provide an exact mass calculation.
bromide is extremely reactive and mostly and quickly combines with anything but the most common is hydrogen While it is true that bromine is reactive and never found in its free state, the question here is "what element is most likely to react with bromine". Although the conditions of the reaction have an influence and mean there can be more than one answer to this question, the most common form of bromine found in ocean water or the earth's crust is sodium bromide, and, more theoretically, sodium is more reactive than hydrogen. Sodium has reacted with the most bromine because sodium itself is quite abundant, and, like bromine, is extremely reactive. The combination of bromine and hydrogen, hydrogen bromide, is almost always manufactured synthetically. Any free HBr in the environment would quickly react with soil or water constituents and most likely would form sodium bromide.
The chemical symbol for hydrogen bromide is HBr.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
The products of the reaction between hydrogen bromide (HBr) and sodium hydroxide (NaOH) are sodium bromide (NaBr) and water (H2O). This is a neutralization reaction where the acid (HBr) reacts with the base (NaOH) to form a salt (NaBr) and water.
NaOH (aq) + HBr (aq) --> H2O (l) + NaBr (aq)
The products of the double-replacement reaction between aqueous hydrogen bromide and aqueous sodium hydroxide are water and sodium bromide. The hydrogen ion from HBr combines with the hydroxide ion from NaOH to form water, while the sodium ion from NaOH combines with the bromide ion from HBr to form sodium bromide.
To find the concentration of HBr, you first need to determine the number of moles of KOH that react with the HBr. This can be done using the volume and concentration of KOH solution. Then, using the stoichiometry of the neutralization reaction between HBr and KOH, you can find the number of moles of HBr present in the sample. Finally, divide the moles of HBr by the volume of the sample (12.0 mL) to obtain the concentration of HBr.
Yes, the products are hydrogen sulfide and iron II bromide. 2HBr + FeS --> FeBr2 + H2S
Sodium Bromide is produced from the reaction of Hydrobromic acid and sodium hydroxide.
The equation for the reaction between hydrobromic acid (HBr) and water (H2O) can be represented as: HBr + H2O → H3O+ + Br-. This reaction involves the transfer of a proton from HBr to water, resulting in the formation of hydronium ion (H3O+) and bromide ion (Br-).
Using the balanced chemical equation for the reaction between HBr and NaOH (1:1 ratio), we can determine the moles of NaOH used. From the volume of NaOH used, we can then calculate the moles of HBr present in the sample. Finally, dividing moles of HBr by the initial volume of the sample (in liters) gives the molar concentration of HBr.
This is a Neutralization reaction. HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)
Ka = [H+].[Br-] / [HBr] However the value of this expression is very high, because HBr is a STRONG acid, meaning that much more than 99.9% of the HBr molecules in water are protolized (ionized), making [H+] and [Br-] equal to the original (added) HBr amount, and the [HBr]-value nearly zero.
HBR doesn't react with Propane, but it does with Propene. The product is either 1-bromo propane(minor product) or 2-bromo propane(major product). To determine which product will be the major product, use the Markovnikov's rule.