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What is the concentration of a HBr if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
To find the concentration of HBr, you first need to determine the number of moles of KOH that react with the HBr. This can be done using the volume and concentration of KOH solution. Then, using the stoichiometry of the neutralization reaction between HBr and KOH, you can find the number of moles of HBr present in the sample. Finally, divide the moles of HBr by the volume of the sample (12.0 mL) to obtain the concentration of HBr.
What is the chemical equation for a heated iron fillings and sulfur powder?
When heated, iron filings (Fe) react with sulfur (S) to form iron sulfide (FeS). The chemical equation for this reaction is: Fe + S -> FeS.
What is the equation for hydrobromic acid and water?
The equation for the reaction between hydrobromic acid (HBr) and water (H2O) can be represented as: HBr + H2O → H3O+ + Br-. This reaction involves the transfer of a proton from HBr to water, resulting in the formation of hydronium ion (H3O+) and bromide ion (Br-).
What will happen when you add cs2 to fe plus s and fes?
When CS2 is added to reaction mixture Fe + S = FeS , it would dissolve the excess 'S' leaving the solids Fe and FeS without any change.
What kind does HBr and CsOH form?
This is a Neutralization reaction. HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)
What is the concentration of a HBr if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
To find the concentration of HBr, you first need to determine the number of moles of KOH that react with the HBr. This can be done using the volume and concentration of KOH solution. Then, using the stoichiometry of the neutralization reaction between HBr and KOH, you can find the number of moles of HBr present in the sample. Finally, divide the moles of HBr by the volume of the sample (12.0 mL) to obtain the concentration of HBr.
What is the chemical equation for a heated iron fillings and sulfur powder?
When heated, iron filings (Fe) react with sulfur (S) to form iron sulfide (FeS). The chemical equation for this reaction is: Fe + S -> FeS.
What is the equation for hydrobromic acid and water?
The equation for the reaction between hydrobromic acid (HBr) and water (H2O) can be represented as: HBr + H2O → H3O+ + Br-. This reaction involves the transfer of a proton from HBr to water, resulting in the formation of hydronium ion (H3O+) and bromide ion (Br-).
What happn when HBr react with sodium thiosulphate?
Dilute Hydrobromic acid react with Sodium Thiosulfate to produce Sodium Bromide, Sulfur Dioxide, Sulfur and Water, according to the following equationNa2S2O3 +2 HBr ----> 2 NaBr + S + SO2+ H2O
What will happen when you add cs2 to fe plus s and fes?
When CS2 is added to reaction mixture Fe + S = FeS , it would dissolve the excess 'S' leaving the solids Fe and FeS without any change.
What type of reaction is fes 2hci feci2 h2s?
This is a double displacement reaction. Iron(II) sulfide (FeS) and hydrochloric acid (HCl) react to form iron(II) chloride (FeCl2) and hydrogen sulfide gas (H2S).
What kind does HBr and CsOH form?
This is a Neutralization reaction. HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)
What is the chemical equation for heating Fe and S?
ordinary mixing is a physical change but when you get to heat them products are formed and it is a chemical change.
When was Fes created?
Fes was created in 789.
What is the population of Fes?
Fes's population is 1,044,376.
When hbr react with propane the p is roduct?
HBR doesn't react with Propane, but it does with Propene. The product is either 1-bromo propane(minor product) or 2-bromo propane(major product). To determine which product will be the major product, use the Markovnikov's rule.
Write the expression for Ka for the dissociation of HBr?
Ka = [H+].[Br-] / [HBr] However the value of this expression is very high, because HBr is a STRONG acid, meaning that much more than 99.9% of the HBr molecules in water are protolized (ionized), making [H+] and [Br-] equal to the original (added) HBr amount, and the [HBr]-value nearly zero.
