This is a Neutralization reaction.
HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)
HBr has an ionic bond.
CsOH is a strong base
CsOH is a strong base
single covalent bond
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
HBr has an ionic bond.
CsOH is a strong base
CsOH is a strong base
single covalent bond
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
HBrO is a weak acid. In solution it partially deprotinates to form BrO- and H+
HBr
HBr has a dipole
yes HBr is an electrolyte
Ka = [H+].[Br-] / [HBr] However the value of this expression is very high, because HBr is a STRONG acid, meaning that much more than 99.9% of the HBr molecules in water are protolized (ionized), making [H+] and [Br-] equal to the original (added) HBr amount, and the [HBr]-value nearly zero.
No. HBr is a strong acid.
C18H25NO•HBr