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The net ionic equation for the given reaction would be: H+ + OH- -> H2O
The net ionic equation for HF and NaOH is: HF (aq) + NaOH (aq) -> H2O (l) + NaF (aq).
Nothing happens:Br- + I- + HCl --> Br- + I- + H+ + Cl-
The net ionic equation for the reaction between hydrofluoric acid (HF) and sodium hydroxide (NaOH) is: HF + OH- -> F- + H2O
The ionic equation for HCl and KHCO3 is H+(aq) + Cl-(aq) + K+(aq) + HCO3-(aq) → KCl(aq) + H2O(l) + CO2(g). The net ionic equation is H+(aq) + HCO3-(aq) → H2O(l) + CO2(g).
The net ionic equation for the given reaction would be: H+ + OH- -> H2O
H+(aq)+OH−(aq)→H2O(l)
The net ionic equation for HF and NaOH is: HF (aq) + NaOH (aq) -> H2O (l) + NaF (aq).
Nothing happens:Br- + I- + HCl --> Br- + I- + H+ + Cl-
The eqnet ionic equation is HCN + OH- --> H2O + CN-
The net ionic equation for the reaction between hydrofluoric acid (HF) and sodium hydroxide (NaOH) is: HF + OH- -> F- + H2O
The ionic equation for HCl and KHCO3 is H+(aq) + Cl-(aq) + K+(aq) + HCO3-(aq) → KCl(aq) + H2O(l) + CO2(g). The net ionic equation is H+(aq) + HCO3-(aq) → H2O(l) + CO2(g).
The net ionic equation for barium hydroxide (Ba(OH)2) plus hydrobromic acid (HBr) is Ba(OH)2 + 2H+ + 2Br- -> Ba2+ + 2Br- + 2H2O. This equation highlights the formation of barium ions (Ba2+) and water molecules (H2O) as the only significant species in the reaction.
complete HCL(aq) + NH3(l) ---> NH4+(aq) + Cl-(aq) net ionic H+(aq) + NH3(aq) ---> NH4+(aq)
NaCN + H2O ---> CN-+ H3O++ Na+ In that equation Na+ is just a spectator ion,, further reaction with water results in: CN- + H2O ---> HCN + OH- thus causing the resulting equation to be basic
The net ionic equation for the reaction between sodium carbonate (Na2CO3) and hydrochloric acid (HCl) is: CO3^2- + 2H^+ -> H2O + CO2. This net ionic equation represents the reaction of carbonate ions with hydrogen ions to form water and carbon dioxide.
To write the net ionic equation for NaOH + H2C4H4O6, first write the balanced molecular equation: NaOH + H2C4H4O6 -> NaC4H4O6 + H2O. Then, split the compounds into ions and remove spectator ions: Na+ + OH- + H2C4H4O6 -> Na+ + C4H4O6^2- + H2O. The net ionic equation is OH- + H2C4H4O6 -> C4H4O6^2- + H2O.