The ionic equation for HCl and KHCO3 is H+(aq) + Cl-(aq) + K+(aq) + HCO3-(aq) → KCl(aq) + H2O(l) + CO2(g). The net ionic equation is H+(aq) + HCO3-(aq) → H2O(l) + CO2(g).
The net ionic equation for the reaction between HPO42- and HCl is: HPO42- + 2H+ -> H2PO4- + Cl-. The spectator ion in this reaction is Cl-.
Nothing happens:Br- + I- + HCl --> Br- + I- + H+ + Cl-
HCl + NH4OH -> NH4Cl + H2O
The net ionic equation for the reaction between HCl and Na2CO3 is 2H+ (aq) + CO3^2- (aq) -> H2O (l) + CO2 (g). This indicates the formation of water and carbon dioxide gas as products.
Only H+ (from the strong perchloric acid) and H2PO4- will react, but ClO4- and Na+ will not and stay unchanged in solution.H+ + H2PO4- --> H3PO4
The net ionic equation for the reaction between HPO42- and HCl is: HPO42- + 2H+ -> H2PO4- + Cl-. The spectator ion in this reaction is Cl-.
Nothing happens:Br- + I- + HCl --> Br- + I- + H+ + Cl-
HCl + NH4OH -> NH4Cl + H2O
The net ionic equation for the reaction between HCl and Na2CO3 is 2H+ (aq) + CO3^2- (aq) -> H2O (l) + CO2 (g). This indicates the formation of water and carbon dioxide gas as products.
Only H+ (from the strong perchloric acid) and H2PO4- will react, but ClO4- and Na+ will not and stay unchanged in solution.H+ + H2PO4- --> H3PO4
2 HCl + Pb --> PbCl2 + H2 (for Pb 2+) 4 HCl + Pb --> PbCl4 + 2 H2 (for Pb 4+)
The net ionic equation for the reaction between NaOH and HCl is: OH- + H+ --> H2O. This equation represents the formation of water from the combination of hydroxide ions and hydrogen ions. Sodium and chloride ions are spectators in this reaction and are not involved in the formation of the products.
Apparently this is a trick question. Cu is too low in reactivity to actually have a reaction with the acid. So there is no reaction. Cu + HCl --> N/R
The net ionic equation for the reaction between hydrochloric acid (HCl) and magnesium (Mg) is: 2H⁺ + Mg(s) -> Mg²⁺ + H₂(g)
what is the net ionic equation of Zn + HCL
complete HCL(aq) + NH3(l) ---> NH4+(aq) + Cl-(aq) net ionic H+(aq) + NH3(aq) ---> NH4+(aq)
To determine the net ionic equation, write out the balanced molecular equation first. Then, write the complete ionic equation with all ions separated. Finally, cancel out spectator ions (ions that appear on both sides of the equation) to arrive at the net ionic equation, which shows only the reacting ions.