The net ionic equation for the reaction between HCl and Na2CO3 is 2H+ (aq) + CO3^2- (aq) -> H2O (l) + CO2 (g). This indicates the formation of water and carbon dioxide gas as products.
To solve this problem, we need to use the balanced chemical equation between HCl and Na2CO3. From the equation, we can see that it is a 1:2 ratio for HCl to Na2CO3. Therefore, we need twice the volume of 0.161 M Na2CO3 to react completely with HCl. Calculate the volume of HCl required by multiplying the volume of Na2CO3 by 2.
Word equations are not unique, but one version would be, "Two formula masses of aquated sodium hydroxide react with one molar mass of carbon dioxide dissolved in the same solution as the sodium hydroxide to yield one formula mass of aquated sodium carbonate and one molar mass of water."
The reaction between Na2CO3 (sodium carbonate) and HCl (hydrochloric acid) produces NaCl (sodium chloride), H2O (water), and CO2 (carbon dioxide). The balanced chemical equation for this reaction is: Na2CO3 + 2HCl -> 2NaCl + H2O + CO2.
The ionic equation for the reaction between hydrochloric acid (HCl) and methylamine (CH3NH2) is: HCl + CH3NH2 -> CH3NH3+ + Cl-
Yes, it will neutralize the HCl and form carbonic acid, which is not stable and decomposes to form CO2. The overall reaction is: Na2CO3 + 2HCl ---> 2NaCl + H2O + CO2, and takes place in two stages: Stage I: sodium carbonate is converted to sodium hyrogen carbonate (NaHCO3) as shown in the reaction: Na2CO3 + HCl ---> NaHCO3 + NaCl Stage II: the gas, carbon dioxide is released NaHCO3 + HCl ---> NaCl + H20 + CO2 The net ionic equation is: CO32- + 2H+ ---> H2O + CO2
The chemical equation is:Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2O
To solve this problem, we need to use the balanced chemical equation between HCl and Na2CO3. From the equation, we can see that it is a 1:2 ratio for HCl to Na2CO3. Therefore, we need twice the volume of 0.161 M Na2CO3 to react completely with HCl. Calculate the volume of HCl required by multiplying the volume of Na2CO3 by 2.
Word equations are not unique, but one version would be, "Two formula masses of aquated sodium hydroxide react with one molar mass of carbon dioxide dissolved in the same solution as the sodium hydroxide to yield one formula mass of aquated sodium carbonate and one molar mass of water."
The reaction between Na2CO3 (sodium carbonate) and HCl (hydrochloric acid) produces NaCl (sodium chloride), H2O (water), and CO2 (carbon dioxide). The balanced chemical equation for this reaction is: Na2CO3 + 2HCl -> 2NaCl + H2O + CO2.
The ionic equation for the reaction between hydrochloric acid (HCl) and methylamine (CH3NH2) is: HCl + CH3NH2 -> CH3NH3+ + Cl-
methyl orange
Yes, it will neutralize the HCl and form carbonic acid, which is not stable and decomposes to form CO2. The overall reaction is: Na2CO3 + 2HCl ---> 2NaCl + H2O + CO2, and takes place in two stages: Stage I: sodium carbonate is converted to sodium hyrogen carbonate (NaHCO3) as shown in the reaction: Na2CO3 + HCl ---> NaHCO3 + NaCl Stage II: the gas, carbon dioxide is released NaHCO3 + HCl ---> NaCl + H20 + CO2 The net ionic equation is: CO32- + 2H+ ---> H2O + CO2
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The balanced equation for NaCO3 + HCl is: Na2CO3 + 2HCl -> 2NaCl + H2O + CO2. Balancing the equation involves making sure there are the same number of each type of atom on both the reactant and product sides.
Youwill getCO2 (g) + H2O (l) + NaCL(aq)don't forget to balance the equation!!!
To balance the chemical equation between hydrochloric acid (HCl) and sodium carbonate (Na2CO3), you first write the unbalanced equation: HCl + Na2CO3 -> NaCl + H2O + CO2. Then you balance the equation by ensuring the same number of each type of atom on both sides of the equation, which in this case would be: 2HCl + Na2CO3 -> 2NaCl + H2O + CO2.
The net ionic equation for the reaction between HPO42- and HCl is: HPO42- + 2H+ -> H2PO4- + Cl-. The spectator ion in this reaction is Cl-.