Apparently this is a trick question. Cu is too low in reactivity to actually have a reaction with the acid. So there is no reaction. Cu + HCl --> N/R
Balanced equation: Cu(CH3COO)2 + Na2CO3 -> CuCO3 + 2CH3COONa Net ionic equation: Cu^2+ + CO3^2- -> CuCO3
The net ionic equation for iron II chloride (FeCl2) and copper (Cu) is: Fe2+ (aq) + Cu(s) → Fe(s) + Cu2+ (aq)
molecular equation: CuSO4 (aq)+Fe (s) --> Cu(s) + FeSO4(aq) net ionic equation: Cu2+(aq) + Fe2+ (s) --> Cu2+(s) + Fe2+(aq) spectator ion: Sulfate Ion (SO42-)
The net ionic equation for the reaction between zinc and copper(II) sulfate is: Zn(s) + Cu2+ (aq) -> Zn2+ (aq) + Cu(s). This equation shows the transfer of electrons between zinc and copper ions, resulting in zinc ions in solution and solid copper being formed.
Copper will not react with hydrochloric acid. Cu(s) + HCl(aq) ---> No reaction
Balanced equation: Cu(CH3COO)2 + Na2CO3 -> CuCO3 + 2CH3COONa Net ionic equation: Cu^2+ + CO3^2- -> CuCO3
The net ionic equation for iron II chloride (FeCl2) and copper (Cu) is: Fe2+ (aq) + Cu(s) → Fe(s) + Cu2+ (aq)
The molecular equation for Cu(NO3)2 and Zn is Cu(NO3)2 + Zn -> Zn(NO3)2 + Cu. The total ionic equation is Cu^2+ + 2NO3- + Zn -> Zn^2+ + 2NO3- + Cu. The net ionic equation is Cu^2+ + Zn -> Zn^2+ + Cu.
molecular equation: CuSO4 (aq)+Fe (s) --> Cu(s) + FeSO4(aq) net ionic equation: Cu2+(aq) + Fe2+ (s) --> Cu2+(s) + Fe2+(aq) spectator ion: Sulfate Ion (SO42-)
Cu(s) + 2H^+(aq) ==> H2(g) + Cu^2+
The net ionic equation for the reaction between zinc and copper(II) sulfate is: Zn(s) + Cu2+ (aq) -> Zn2+ (aq) + Cu(s). This equation shows the transfer of electrons between zinc and copper ions, resulting in zinc ions in solution and solid copper being formed.
Balanced Molecular EquationCu(NO3)2(aq) + 2LiOH(aq) ---> 2LiNO3(aq) + Cu(OH)2(s)Full (Complete) Ionic Equation (All of the ions in the reaction are shown.)Cu2+(aq) + 2NO3-(aq) --> + 2Li+(aq) + 2NO3-(aq) + Cu(OH)2(s)Net Ionic Equation (Only the ions that reacted and the precipitate that formed are shown.)Cu2+(aq) + 2OH-(aq) --> Cu(OH)2(s)
Copper will not react with hydrochloric acid. Cu(s) + HCl(aq) ---> No reaction
The net ionic equation for the reaction between potassium carbonate (K2CO3) and copper(II) chloride (CuCl2) is: 2K^+ + CO3^2- + Cu^2+ + 2Cl^- → CuCO3(s) + 2K^+ + 2Cl^-
The complete net ionic equation for the reaction between copper sulfate and lead nitrate is: Cu²⁺(aq) + SO₄²⁻(aq) + 2Pb²⁺(aq) + 2NO₃⁻(aq) → PbSO₄(s) + Cu(s) + 2NO₃⁻(aq)
The balanced net ionic equation for when a suspension of copper (II) hydroxide is treated with excess ammonia water is: Cu(OH)2(s) + 4NH3(aq) ⟶ [Cu(NH3)4]2+(aq) + 2OH-(aq)
First you have to write the entire equation (including states): CuSO4(aq)+ 2NaOH(aq) -> Cu(OH)2(s) + Na2SO4(aq) Now you have to write an ionic equation which involves splitting up each compound, that is in aqueous form, into it's parts and writing the charge of each part: Cu(aq)2+ + SO4(aq)2- + 2Na(aq)1+ + 2OH(aq)-1 -> Cu(OH)2(s) + SO4(aq)2- + 2Na(aq)1+ Now to write the net ionic equation, you "cancel" out any thing that is the exact same on both sides of the equation (same state, number, charge). That leaves us with the following: SO4(aq)2- + 2OH(aq)-1 -> Cu(OH)2(s) This is the net ionic equation.