The net ionic equation for the reaction between potassium carbonate (K2CO3) and copper(II) chloride (CuCl2) is:
2K^+ + CO3^2- + Cu^2+ + 2Cl^- → CuCO3(s) + 2K^+ + 2Cl^-
The net ionic equation for K2CO3 is: 2K+ (aq) + CO3^2- (aq) → K2CO3 (s) This equation shows the dissociation of potassium ions and carbonate ions in aqueous solution to form solid potassium carbonate.
what is the net ionic equation of Zn + HCL
CuSO4(aq) + BaCl2(aq) → BaSO4(s) + CuCl2(aq) Net ionic equation: Ba2+(aq) + SO4^2-(aq) → BaSO4(s)
The ionic equation for the reaction between magnesium perchlorate (Mg(ClO4)2) and copper(II) chloride (CuCl2) is: Mg(ClO4)2 (aq) + CuCl2 (aq) -> MgCl2 (aq) + Cu(ClO4)2 (s) The net ionic equation is: Mg2+ (aq) + 2ClO4- (aq) + Cu2+ (aq) + 2Cl- (aq) -> Mg2+ (aq) + 2Cl- (aq) + Cu2+ (aq) + 2 ClO4- (s)
CuCl2(aq) + 2AgNO3(aq) = Cu(NO3)2(aq) + 2AgCl(s)
The net ionic equation for K2CO3 is: 2K+ (aq) + CO3^2- (aq) → K2CO3 (s) This equation shows the dissociation of potassium ions and carbonate ions in aqueous solution to form solid potassium carbonate.
what is the net ionic equation of Zn + HCL
CuSO4(aq) + BaCl2(aq) → BaSO4(s) + CuCl2(aq) Net ionic equation: Ba2+(aq) + SO4^2-(aq) → BaSO4(s)
The ionic equation for the reaction between magnesium perchlorate (Mg(ClO4)2) and copper(II) chloride (CuCl2) is: Mg(ClO4)2 (aq) + CuCl2 (aq) -> MgCl2 (aq) + Cu(ClO4)2 (s) The net ionic equation is: Mg2+ (aq) + 2ClO4- (aq) + Cu2+ (aq) + 2Cl- (aq) -> Mg2+ (aq) + 2Cl- (aq) + Cu2+ (aq) + 2 ClO4- (s)
Cu2+ + (SO4)2- + 2 Na+ + 2 Cl- = CuCl2 = Na2SO4
CuCl2(aq) + 2AgNO3(aq) = Cu(NO3)2(aq) + 2AgCl(s)
To determine the net ionic equation, write out the balanced molecular equation first. Then, write the complete ionic equation with all ions separated. Finally, cancel out spectator ions (ions that appear on both sides of the equation) to arrive at the net ionic equation, which shows only the reacting ions.
To write a net ionic equation from a complete ionic equation, you remove the spectator ions that appear on both sides of the equation. The remaining ions that participate in the reaction are then included in the net ionic equation. This simplifies the equation to show only the ions that undergo a chemical change.
the spectator ions are removed
Barium chloride and sodium sulfate Molecular equation: BaCl2(aq) + Na2SO4(aq)--> BaSO4(s) + 2NaCl(aq) ionic equation: Ba+2(aq) + 2Cl-(aq) + 2Na+(aq) + SO4-2(aq) --> BaSO4(s) + 2Na+(aq) + 2Cl-(aq) Net ionic equation is Ba+2(aq) + SO4-2(aq) --> BaSO4(s)
the spectator ions are removed
Yes. If both compounds are insoluable in water then the complete/overall ionic equation and the net ionic equation will look the same. The only way they look different is if there are spectator ions(ions that appear on both sides of the equation).