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The net ionic equation for the reaction between potassium carbonate (K2CO3) and copper(II) chloride (CuCl2) is:

2K^+ + CO3^2- + Cu^2+ + 2Cl^- → CuCO3(s) + 2K^+ + 2Cl^-

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What Is The Net Ionic Equation For K2Co3?

The net ionic equation for K2CO3 is: 2K+ (aq) + CO3^2- (aq) → K2CO3 (s) This equation shows the dissociation of potassium ions and carbonate ions in aqueous solution to form solid potassium carbonate.


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What is the net ionic equation of copper ii sulfate and sodium chloride?

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Complete net ionic equation agno3 plus NaCl?

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What net ionic equation describes the reaction when these solutions are mixed?

To determine the net ionic equation, write out the balanced molecular equation first. Then, write the complete ionic equation with all ions separated. Finally, cancel out spectator ions (ions that appear on both sides of the equation) to arrive at the net ionic equation, which shows only the reacting ions.


How is a net ionic equation written in a complete ionic equation?

To write a net ionic equation from a complete ionic equation, you remove the spectator ions that appear on both sides of the equation. The remaining ions that participate in the reaction are then included in the net ionic equation. This simplifies the equation to show only the ions that undergo a chemical change.


How is a net ionic equation from a complete ionic equation?

the spectator ions are removed


What is the net ionic equation of barium chloride and potassium carbonate?

Barium chloride and sodium sulfate Molecular equation: BaCl2(aq) + Na2SO4(aq)--> BaSO4(s) + 2NaCl(aq) ionic equation: Ba+2(aq) + 2Cl-(aq) + 2Na+(aq) + SO4-2(aq) --> BaSO4(s) + 2Na+(aq) + 2Cl-(aq) Net ionic equation is Ba+2(aq) + SO4-2(aq) --> BaSO4(s)


How is a net ionic equation written from a ionic equation?

the spectator ions are removed


Can the complete ionic equation and the net ionic equation for a double replacement reaction ever be the same?

Yes. If both compounds are insoluable in water then the complete/overall ionic equation and the net ionic equation will look the same. The only way they look different is if there are spectator ions(ions that appear on both sides of the equation).