CuNO32is not physically, chemically, philosophically, or metaphorically possible, but Copper(II) nitrate is the chemical compound with the formula Cu(NO3)2.
Balanced Molecular:2HBr + Mg = MgBr2 + H2Net Ionic:2Br- + Mg = Mg2+ + 2 Br-
The net ionic equation for this reaction is:3Mg2+(aq) + 2PO43-(aq) -->Mg3(PO4)2(s)How to get this answer:To write the net ionic equation, you can start with the molecular equation:2Na3PO4(aq) + 3Mg(NO3)2(aq) --> 6NaNO3(aq) + Mg3(PO4)2(s)The molecular equation can be used to write the full ionic equation. To do this, you break down everything that is aqueous into its ionic constituents:2Na+(aq) + 2PO43-(aq) + 3Mg2+(aq) + 6NO3-(aq) --> 6Na+(aq) + 6NO3-(aq) + Mg3(PO4)2(s)You can then cross out whatever is the same on both side to get your net ionic equation:3Mg2+(aq) + 2PO43-(aq) -->Mg3(PO4)2(s)
Net Ionic: Pb2+(aq)+SO42-(aq) --> PbSO4(s) Molecular: Pb(NO3)2(aq) + K2SO4(aq) --> PbSO4(s) + 2KNO3(aq)
The net ionic equation is SO42- + Ca2+ CaSO4.
Balanced Molecular EquationCu(NO3)2(aq) + 2LiOH(aq) ---> 2LiNO3(aq) + Cu(OH)2(s)Full (Complete) Ionic Equation (All of the ions in the reaction are shown.)Cu2+(aq) + 2NO3-(aq) --> + 2Li+(aq) + 2NO3-(aq) + Cu(OH)2(s)Net Ionic Equation (Only the ions that reacted and the precipitate that formed are shown.)Cu2+(aq) + 2OH-(aq) --> Cu(OH)2(s)
Molecular equation: CuSO4 + Na2CO3 → CuCO3 + Na2SO4 Net ionic equation: Cu2+ + CO3^2- → CuCO3
To write a total ionic equation from a net ionic equation, start by breaking down the compounds into their respective ions (if they are ionic compounds) and including only the ions that participate in the reaction. To write a molecular equation, simply write out the complete chemical equation including all reactants and products without breaking them down into ions. Remember, a net ionic equation shows only the ions that participate in the reaction, whereas a total ionic equation includes all ions involved.
These two compounds doesn't react.
Molecular Eq HC2H3O2(aq) + NH3(aq) -> NH4+(aq) + C2H3O2-(aq) Ionic Eq H+(aq) + C2H3O2-(aq) + NH3(aq) -> NH4+(aq) + C2H3O2-(aq) Net Ionic Eq H+(aq) + NH3(aq) -> NH4+(aq)
A chemical equation can be interpreted in terms of molecular, ionic, or net ionic equations. In a molecular equation, all reactants and products are written as complete compounds. In an ionic equation, all soluble compounds are dissociated into their respective ions. In a net ionic equation, spectator ions are omitted to show only the species that participate in the chemical reaction.
To determine the net ionic equation, write out the balanced molecular equation first. Then, write the complete ionic equation with all ions separated. Finally, cancel out spectator ions (ions that appear on both sides of the equation) to arrive at the net ionic equation, which shows only the reacting ions.
Yes, the total ionic equation shows all the ions involved in the reaction, including the spectator ions. To find the net ionic equation, you can remove the spectator ions from the total ionic equation to emphasize the ions that participate in the actual chemical change.
Molecular Compound
The chemical reaction is:2 NaOH + CoCl2 = 2 NaCl + Co(OH)2
the spectator ions are removed
Balanced Molecular:2HBr + Mg = MgBr2 + H2Net Ionic:2Br- + Mg = Mg2+ + 2 Br-
chromium disodium phosphate