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The net ionic equation for this reaction is:

3Mg2+(aq) + 2PO43-(aq) -->Mg3(PO4)2(s)

How to get this answer:

To write the net ionic equation, you can start with the molecular equation:

2Na3PO4(aq) + 3Mg(NO3)2(aq) --> 6NaNO3(aq) + Mg3(PO4)2(s)

The molecular equation can be used to write the full ionic equation. To do this, you break down everything that is aqueous into its ionic constituents:

2Na+(aq) + 2PO43-(aq) + 3Mg2+(aq) + 6NO3-(aq) --> 6Na+(aq) + 6NO3-(aq) + Mg3(PO4)2(s)

You can then cross out whatever is the same on both side to get your net ionic equation:

3Mg2+(aq) + 2PO43-(aq) -->Mg3(PO4)2(s)

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