First you have to write the entire equation (including states):
CuSO4(aq)+ 2NaOH(aq) -> Cu(OH)2(s) + Na2SO4(aq)
Now you have to write an ionic equation which involves splitting up each compound, that is in aqueous form, into it's parts and writing the charge of each part:
Cu(aq)2+ + SO4(aq)2- + 2Na(aq)1+ + 2OH(aq)-1 -> Cu(OH)2(s) + SO4(aq)2- + 2Na(aq)1+
Now to write the net ionic equation, you "cancel" out any thing that is the exact same on both sides of the equation (same state, number, charge). That leaves us with the following:
SO4(aq)2- + 2OH(aq)-1 -> Cu(OH)2(s)
This is the net ionic equation.
protiens
OH- + NH4+ --> H2O + (NH3)gas
it starts changing to white because the colour of the copper sulphate solution becomes whote during the process of evaporation
Sodium displaces the sulfate to make sodium sulfate; iron displaces the hydroxide to make ferrous hydroxide which becomes brown.
A balanced equation MUST have EQUAL numbers of EACH type of atom on BOTH sides of the arrow.The correctly balanced equation is:The equation for sodium hydroxide and aluminum sulfate is written as follows.Al2(SO4)3(s) + 6 NaOH(aq) 2 Al(OH)3(s) + 6 Na+(aq) + 3 SO42–(aq)
The products are Sodium Nitrate and Copper Hydroxide.
CuSOβ+2NaOH=NaβSOβ+Cu(OH)ββ
Copper sulfate is a reactant in the equation as stated, because it is present before the reaction has occurred and no longer present afterward.
4Na(OH)3+2CUSO4-->CU2O+H2O+2NA2SO4
protiens
Biuret reagent is made up of sodium hydroxide and copper sulphate.
Copper(II) carbonate is insoluble in water and doesn't react with sodium sulfate. A green product, visible on ald objects made from copper or copper alloys, is a mixture of copper carbonate and copper hydroxide.
No, the mass is conserved.
Sodium hydroxide and sodium sulfate don't actually react.
H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O. Sulfuric Acid + Sodium Hydroxide --> Sodium Sulfate + Water.
Copper chloride + Sodium hydroxide --> Copper hydroxide + sodium chloride
2CuS + NaCO2