Has to be a simple SN1 reaction.
tertiary carbocation, very very stable due to three phenyl groups and very bulky.
The reaction is:CH3NH2 + HBr = CH3NH3Br
acid is hbr and the base is h2o
The reaction is:Sr(OH)2 + 2 HBr = SrBr2 + 2 H2O
The answer is 770,9 mL solution.
This is a Neutralization reaction. HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)
The reaction is:CH3NH2 + HBr = CH3NH3Br
This equation is:HBr + LiOH = LiBr + H2O
acid is hbr and the base is h2o
The reaction is:Sr(OH)2 + 2 HBr = SrBr2 + 2 H2O
NO
The answer is 770,9 mL solution.
This is a Neutralization reaction. HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)
C19H16O
mechanism. mechanism.
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
Br2 + H20 ===> HBr + HOBr
I suppose that the reaction is the following: ZrBr4 + H2O----------ZrOBr2 + 2 HBr