Fluorine has the highest electronegativity of any element. Therefore, the energy released when hydrogen and fluorine react is greater than the energy released when hydrogen and bromine react, and that energy must be resupplied to cause either bond to break.
This is to do with the intermolecular forces in the two compounds. There are no hydrogen bonds between the molecules of either compound, since Br and I are not electronegative enough to polarise the molecules sufficiently. But since HI molecules contain more electrons than HBr, there are increased van der Waals forces in HI. For the same reason HBr has a higher boiling point than HCl, but HF has a higher boiling point than HCl, HBr or HI because of hydrogen bonding.
HBr In a chemical equation you would write it as HBr(aq).
This does not make a buffer because HBr is a STRONG acid, and for a buffer you need a WEAK acid and the salt of the acid.
HBr ok
HBr :]
HBr has an ionic bond.
Br is a halogen, which means that it has 7 valence electrons and needs one more in order to have a complete filled orbital. The H has 1 valence electron and needs 1 more in order to have a filled orbital. While another atom such as sodium bonding with Br would form an ionic bond, this doesn't happen when Br bonds with H due to the fact that the hydrogen atom is a lot smaller and its electron is closer to the nucleus so that it experiences a greater force of attraction to the nucleus. This means a greater amount of force required by the Br in order to "steal" the electron, which is more energy than is required for a covalent bond to form. Therefore, HBr has a coordinate covalent bond instead of an ionic bond.
single covalent bond
HCL has a higher boiling point compared to HBr This is due to difference in electronegativity. H - 2.1 Cl - 3.0 Br - 2.8 The difference for HCl is 0.9, the difference for HBr is 0.7. The larger the difference in electronegavity means the stronger the bond. Large difference means greater attraction hence more energy is needed to overcome this bond.
Polar!
HF > HCl > HBr > HI Hydrogen-bond strength is determined by the electronegativity difference; since fluorine has the smallest radius, it exerts the greatest attractive force over the H+ cation, creating the strongest bond.
Generally HBr is hydrobromic acid which is formed due to the electrovalent or ionic bond between the ions of hydrogen and bromine.
HBr is a polar molecule: dipole-dipole forces. There are also dispersion forces between HBr molecules. The hydrogen bond is a special dipole-dipole interaction between the hydrogen atom in a polar N-H, O-H, or F-H bond and an electronegative O, N, or F atom.
Ka = [H+].[Br-] / [HBr] However the value of this expression is very high, because HBr is a STRONG acid, meaning that much more than 99.9% of the HBr molecules in water are protolized (ionized), making [H+] and [Br-] equal to the original (added) HBr amount, and the [HBr]-value nearly zero.
actually HBr is stronger acid than HCl so i think you got something mixed up
The Lewis dot structure for hydrogen bromide (HBr) consists of a single covalent bond between the hydrogen atom and the bromine atom. So, there is one single covalent bond in the Lewis dot structure of HBr.
They are both linear, because both have only two atoms. HBr is more polar than br2, because H and Br are different atoms. So, the bond is polar, given that H and Br have differing capacities to attract electrons