1.25 mol HBr is (maximally) produced from 1.25 mol Br (better: 0.625 mol Br2)
Since its molecular mass is 80.91 g mol−1 this 1.25 mol corresponds with 101.1 gram HBr
Considering conservation of mass, the mass will not be destroyed or gained. This means that there will be 20 grams of hydrogen flouride.
Dilute Hydrobromic acid react with Sodium Thiosulfate to produce Sodium Bromide, Sulfur Dioxide, Sulfur and Water, according to the following equationNa2S2O3 +2 HBr ----> 2 NaBr + S + SO2+ H2O
Bromine itself is not considered an acid. However, it can react with water to a small degree to form hydrobromic acid (HBr), a strong acid and hypobromous acid (HBrO) a weak acid. Br2 + H2O --> HBr + HBrO
Fluorine has the highest electronegativity of any element. Therefore, the energy released when hydrogen and fluorine react is greater than the energy released when hydrogen and bromine react, and that energy must be resupplied to cause either bond to break.
HBr In a chemical equation you would write it as HBr(aq).
For this you need the atomic (molecular) mass of HBr. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. HBr= 81.0 grams186 grams HBr / (81.0 grams) =2.30 moles HBr
Considering conservation of mass, the mass will not be destroyed or gained. This means that there will be 20 grams of hydrogen flouride.
HCl effuses faster due to less molecular mass (36.5) as compare to HBr (81).
Dilute Hydrobromic acid react with Sodium Thiosulfate to produce Sodium Bromide, Sulfur Dioxide, Sulfur and Water, according to the following equationNa2S2O3 +2 HBr ----> 2 NaBr + S + SO2+ H2O
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
HBR doesn't react with Propane, but it does with Propene. The product is either 1-bromo propane(minor product) or 2-bromo propane(major product). To determine which product will be the major product, use the Markovnikov's rule.
HBr + H2O = HBr(aq) Hydrogen bromide, like hydrogen chloride, does not react with water. it just dissolves into the water. HBr(g) + H2O(l) = H3O^+(aq) + Br^-(aq)
3.8 g Fe * 1 mol Fe/55.85 g Fe (molar mass) = .0680 mol Fe .0680 mol Fe * 2 mol HBr/1 mol Fe (found in formula Fe+2HBr=>FeBr2+H2)=.136 mol HBr .136 mol HBr*80.912 g HBr/1 mol HBr=11.004 g HBr (or 11 using 2 sig figs) And the mass of H2 that is produced is 0.14 g
The mass of solid AgBr that is produced when 100.0 ml of 0.150 M AgNO3 is added to 20.0 ml of 1.00 M NaBr 2.82g.
Yes, the products are hydrogen sulfide and iron II bromide. 2HBr + FeS --> FeBr2 + H2S
HBr
HBr has a dipole