You don't. The solenoid's voltage rating means that it needs that much voltage to operate correctly.
It is 64v5u2.
No, the charging voltage needs to closely match the battery or BOOM!
1967 Mustang specs:Available Engines:200cid 6cyl 1V 120hp289cid 2V V-8 200hp289cid 4V V-8 225hp289cid 4V V-8 271hp390cid 4V V-8 320hp
The answer is -4v + 83v^2.
4V
Yes I can. = v-16-4v = -4v-2 = you have to move all the variables to one side, and all the numbers to the other side... v - 4v + 4v = 16 -2 v= 14
260
it equals 3+4v
It is equal to: 20v^2 +4v -24
Solve S = 4v2 for v . -4(4-v)= -2(2v-1) v-16+4v = -2(2v-1) v-16+4v = -4v + 2 -16+5v = -4v + 2 5v = -4v + 18 9v = 18 v = 2
-8-3v = 4v+48 -3v-4v = 48+8 -7v = 56 v = -8
Lets take the basic case of if you have a 2V battery with a resistor going from the positive terminal to the negative one. V = i*R and P = V*i are the two equations that you need to know; solve the first one for i, so i= V/R and sub it into the second equation, so P = V*V/R, or P = V^2/R. Now you can see in this setup, if you double the voltage, the power is multiplied by 4.