Java program to print odd numbers using while loop?

Answer 1

#include#includevoid main()int n;printf("enter any number");scanf("%d",&n);while(n%2==0)printf("enter the number is even");elseprintf("enter the number is odd");}getch()

Answer 2

/* write a c program to sum even number by getting input from user*/

#include <iostream.h>

int main(void)

{

int num = 1;

int sum = 0;

int upperlimit;

printf("Enter the upperlimit:");

scanf("%d", &upperlimit);

while( num <= upperlimit)

{

if(num % 2 == 0)

{

sum += num;

num += 1;

}

}

printf("The sum of the even num is 5d\n", sum);

return 0;

}

Above is my code to determine even number sum i dont know what is error in it i have try to remove the error but program execute well didn't display the required result....

Answer 3

void main() { int i=0; printf("Even numbers in: [0,20]"); while(i<=20) { printf("%d\t", i); i += 2; } }

Answer 4

#include<stdio.h>

main()

{

int i=1;

while(i<=20)

{

printf("%d",i);

i=i+2

}

}

Answer 5

Following for whole numbers....

If number mod 2 Then

add code for even number

Else

add code for odd number

End If

Answer 6

Something like this:

int i = 1;

while (i <= 100) {

System.out.print(i, ' ');

i+=2;

}