due per tre
x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)
1) itaalia keel - Italian language 2) itaallane - an Italian person
x3-x2
x3 - x2 + x - 2 has no rational factors.
It is -2*(3x2 - 7)*(x3 - 7x)-3
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
x3
75x3, /2, +1, x3...10 x3=30 /2=15 +1=16 x3=48 /2=24 +1=25 x3=75
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)
X3 - 4 = 2 X3 = 6 X = 61/3 X = about 1.817
7