It is very simple
silver chloride is soluble in ammonia, lead chloride is only slightly soluble in ammonia
Add ammonia solution to mix. Silver chloride dissolves leaving lead chloride behind.
Lead chloride dissolves in hot water, whereas lead sulphate does not. Mix the sample with hot water and filter off the lead sulphate, then evaporate the water and dry the solid left behind to recover the lead chloride.
Silver Nitrate + Sodium Chloride --> Silver Chloride + Sodium Nitrate AgNO3 + NaCL --> AgCL + NaNO3
no, lead (II) chloride is NOT soluble. Therefore, it will remain a solid.----------- I know that lead (II) chloride is soluble in hot water. I did it yesterday. I don't know what happens if its cold water, but PbCl2 is soluble in hot water.PbCl2(s)---heat---> Pb2+(aq)+2Cl-(aq)
silver chloride is soluble in ammonia, lead chloride is only slightly soluble in ammonia
Add ammonia solution to mix. Silver chloride dissolves leaving lead chloride behind.
Dissolve the mixture in water. The precipitate is lead chloride. By filtering the solution and followed by evaporation, sodium chloride can be extracted.
by adding hot water
none
Lead(ii) Iodide is a yellow precipitate while silver chloride is white.
They are simply separated by Sublimation process , heat the mixture in an open container and put a large inverted funnel on container the Ammonium chloride becomes sublimed and its white crystals becomes deposited on the walls of funnel leaving the Lead chloride in container.
separate mixtures into their componets lead and aluminum pellets
FIRE ;)
No, not the lead
Lead chloride dissolves in hot water, whereas lead sulphate does not. Mix the sample with hot water and filter off the lead sulphate, then evaporate the water and dry the solid left behind to recover the lead chloride.
Filter it off, sieve it or use decantation