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The precipitate will be barium sulfate. The reaction is as follows:BaCl2(aq) + Na2SO4(aq) ==> 2NaCl(aq) + Ba(SO4)(s)
K+ and Cl- react to form KCl (potassium chloride)
Yes, in this case you would have an aqueous solution of sodium chloride and acetic acid.
The formula unit for the formation of potassium chloride and barium sulfate is one mole. One unit of potassium sulfate and barium chloride are required for the reaction.
Hydrochloric Acid (HCl), because HCl in aqueous solution form ions H^(+) & Cl^(-) It is the Cl(-) anion that combines with then potassium cation to form that salt potassium chloride (KCl). Here is the balanced reaction eq'n HCl(aq) + KOH(aq) = KCl(aq) + H2O(l)
Yes, it is correct.
2KI + Cl2 = 2KCl + I2
This is the correct answer: Cl2(g)+2KI(aq) = I2(s)+2KCl(aq)
In aqueous solution they would not react. They would form a solution of ferric ions, chloride ions, potassium ions, and iodide ions.
Chlorine is more reactive than bromine thus bromine is unable to displace chlorine to form potassium bromide.
Potassium chloride, KCl, is a salt; it dissolves in water and would be considered a solute when it does so.
The precipitate will be barium sulfate. The reaction is as follows:BaCl2(aq) + Na2SO4(aq) ==> 2NaCl(aq) + Ba(SO4)(s)
Sodium chloride may form aqueous solutions.
Potassium chloride is react with AgNO3 , the chloride ion subtract from potassium chloride to form silver chloride precipitate and potassium nirate. KCl + AgNO3 → KNO3 + AgCl↓
One example is the reaction between the aqueous solutions lead nitrate, Pb(NO3)2 and potassium chloride, KCl. They react to form solid (a precipitate) lead chloride, PbCl2, and aqueous potassium nitrate, KNO3. The balanced equation is Pb(NO3)2(aq) + KCl(aq) ---> PbCl2(s) + KNO3(aq)
Potassium form in water potassium hydroxide; so the reaction will be:2 KOH + Zn(NO3)2 = 2 KNO3 + Zn(OH)2(s)
K+ and Cl- react to form KCl (potassium chloride)