Here is the equation:
Cl2(aq) + 2 KI(aq) ----> 2 KCl(aq) + I2(aq)
Aqueous chlorine will react with aqueous sodium iodide to form aqueous sodium chloride and iodine. The balanced chemical equation for this reaction is: Cl2 (aq) + 2NaI (aq) -> 2NaCl (aq) + I2 (s)
The reaction between potassium iodide (KI) and chlorine gas (Cl2) forms potassium chloride (KCl) and iodine (I2). The balanced equation is 2KI + Cl2 → 2KCl + I2.
The net ionic equation for the reaction of aqueous potassium iodide with aqueous lead (II) nitrate is: 2I⁻(aq) + Pb²⁺(aq) -> PbI₂(s)
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
Yes, it is correct.
This is the correct answer: Cl2(g)+2KI(aq) = I2(s)+2KCl(aq)
2KI + Cl2 = 2KCl + I2
When chlorine is added to potassium iodide, it will undergo a redox reaction. Chlorine will oxidize iodide ions in potassium iodide to form iodine and chloride ions. The overall reaction can be represented as Cl2 + 2KI -> 2KCl + I2.
Aqueous chlorine will react with aqueous sodium iodide to form aqueous sodium chloride and iodine. The balanced chemical equation for this reaction is: Cl2 (aq) + 2NaI (aq) -> 2NaCl (aq) + I2 (s)
The reaction between potassium iodide (KI) and chlorine gas (Cl2) forms potassium chloride (KCl) and iodine (I2). The balanced equation is 2KI + Cl2 → 2KCl + I2.
Chlorine gas reacts with potassium iodide to produce potassium chloride and iodine. This reaction can be represented by the chemical equation: Cl2 + 2KI -> 2KCl + I2.
The net ionic equation for the reaction of aqueous potassium iodide with aqueous lead (II) nitrate is: 2I⁻(aq) + Pb²⁺(aq) -> PbI₂(s)
When chlorine gas is bubbled into an aqueous solution of potassium iodide, some of the iodide ions are oxidized to iodine. The iodine molecules combine with iodide ions to form brown triiodide ion, I3-. In this demonstration, the aqueous solution is above a layer of carbon tetrachloride, in which iodine is quite soluble. The beautiful violet color of iodine can be seen as the iodine dissolves in the carbon tetrachloride layer. With excess chlorine, iodine reacts to form iodine monochloride, ICl, which is ruby red. The iodine monochloride reacts further to form iodine trichloride, ICl3, which is much lighter in color, causing the solution to be decolorized.
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
The dark red-brown color change occurs because the chlorine oxidizes iodide ions to form iodine, which reacts with excess iodide ions to form triiodide ions. These triiodide ions absorb light in the visible range, resulting in the dark red-brown color observed in the solution.
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate