x^3-x
= x(x^2-1)
= x(x+1)(x-1)
24
X squared plus 1 and x minus 1 ---- Actually it is the following: x3-x x(x2-1) x(x+1)(x-1)
(x - 1)(x^2 + x + 1)
5x - 4x = x
x^3 - x^3 = 0 Remember , whilst 'x' is an unknown value, that unkonwn is a fixed value. As a numerical example 3^(3) - 3^(3) = 27 - 27 = 0 The '3' is 'x' in this case
X cubed - X cubed is zero.
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
it equals 5
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
x(x + 3)(x - 4)
The answer is -x3 + x
x cubed minus 216
24
x cubed, or x³
2x(x−6)(x+1)
(x - 2)(x^2 + x + 3)
(x - 5)(x^2 + 1)