Plug and chug!
14 + 2(1) - 4(3)
14 + 2 - 12
= 4
====
7x + 51x + 14= 58x + 14= 2(29x + 7)
7y+5=-9... 7y must equal -14 therefore y must be -2
14 ________________ 14
Solve for e: 3d = 3e + 14 subtract 14 to both sides 3d - 14 = 3e divde by 3 to both sides d - 14/3 = e
14 + 78 = 92
13.3
7x + 51x + 14= 58x + 14= 2(29x + 7)
14 + 14 = 28
7y+5=-9... 7y must equal -14 therefore y must be -2
A is 14
Solve for e: 3d = 3e + 14 subtract 14 to both sides 3d - 14 = 3e divde by 3 to both sides d - 14/3 = e
14 ________________ 14
14 + 11 + 3 = 28
14 + 3 + 11 = 28
It can't be solved because the discriminant of this quadratic equation is less than zero
14 + 78 = 92
No, it does not.