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There will be 4 possible solutions if all you are looking for is the angles, so you will need to find out which quadrant your angle is in.

2sinÂ²x = sin x **Subtract sin x from both sides.

2sinÂ²x - sin x = 0 **Then factor out sin x.

sin x(2sin x - 1) = 0 **Set each equal to zero. (AB=0 is the same as A=0 OR B=0).

sin x = 0 or 2sin x - 1 = 0 to 2sin x = 1 to sin x = 1/2

At this point all that is left to do is find out where sin x = 0 or 1/2, which is 0, 180 for sin x = 0 or 30, 150 for sin x = 1/2.

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0Do sin(x), square it, and then multiply it by two.

It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!

Answer 1 Put simply, sine squared is sinX x sinX. However, sine is a function, so the real question must be 'what is sinx squared' or 'what is sin squared x': 'Sin(x) squared' would be sin(x^2), i.e. the 'x' is squared before performing the function sin. 'Sin squared x' would be sin^2(x) i.e. sin squared times sin squared: sin(x) x sin(x). This can also be written as (sinx)^2 but means exactly the same. Answer 2 Sine squared is sin^2(x). If the power was placed like this sin(x)^2, then the X is what is being squared. If it's sin^2(x) it's telling you they want sin(x) times sin(x).

sin(x)*sin2(x) = 1 so sin3(x) = 1 so that sin(x) = cuberoot(1) = 1 then x = pi/2 + n*pi where n is an integer.

2 sin2(x) + sin(x) - 1 = 0(2 sin + 1) (sin - 1) = 0Either 2 sin(x) + 1 = 02sin(x) = -1sin(x) = -0.5x = 210Â°, 330Â°or sin(x) - 1 = 0sin(x) = 1x = 90Â°

2 x cosine squared x -1 which also equals cos (2x)

2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))

sin2 x = (1/2)(1 - cos 2x) cos2 x = (1/2)(1 + cos 2x) Multiplying both you get (1/4) (1 - cos2 2x) Which is equal to (1/4) (1 - (1/2) (1 + cos 4x) = (1/8) (2 - 1 - cos 4x) = (1/8) (1 - cos 4x) Or If it is the trigonomic function, sin squared x and cosine squared x is equal to one

The answer is 1. sin^2 x cos^2/sin^2 x 1/cos^2 cos^2 will be cancelled =1 sin^2 also will be cancelled=1 1/1 = 1

That's 13.

The deriviative of sin2 x + cos2 x is 2 cos x - 2 sin x

To solve 2 cos2x + sin x - 1 make use of the identity cos2x + sin2x = 1, then: cos2x = 1 - sin2x and 2 cos2x + sin x - 1 = 2 (1 - sin2x) + sin x - 1 = 2 - 2 sin2x + sin x - 1 = 1 + sin x - 2 sin2 x if you let y = sin x, then you can see you have a quadratic: 1 + sin x - 2 sin2 x = 1 + y - 2y2 which can be solved for 1 + y - 2y2 = 0: 1 + y - 2y2 = 0 ⇒ 2y2 - y - 1 = 0 ⇒ (2y + 1)(y - 1) = 0 ⇒ y = -1/2 or 1 but y = sin x, so: sin x = -1/2 or sin x = 1 and so solve these for x.

Solve sin² x = sin x. The answer is x = 0 or π/2 or π. Here's how you can find this result: Let s = sin x. Then, we have, s² - s = 0; whence, s(s - 1) = 0. Now, when the product of two numbers is zero, then one or other of them must equal zero. Hence, either, s = 0 OR s - 1 = 0; that is, sin x = 1 or 0. For 0 ≤ x < 360°, x = 0° or 90° or 180°; those being the only angles whose sine equals either 1 or 0. In term of radian measure, x = 0 or π/2 or π.

2 sin2 x + sin x = 1. Letting s = sin x, we have: 2s2 + s - 1 = (2s - 1)(s + 1) = 0; whence, sin x = ½ or -1, and x = 30° or 150° or 270°. Or, if you prefer, x = π/6 or 5π/6 or 3π/2.

4x4=16 or 2^4=16

9 plus 2 squared is equal to 13.

sin2 + cos2 = 1 So, (1 - 2*cos2)/(sin*cos) = (sin2 + cos2 - 2*cos2)/(sin*cos) = (sin2 - cos2)/(sin*cos) = sin2/(sin*cos) - cos2/(sin*cos) = sin/cos - cos-sin = tan - cot

1 squared plus 8 squared or 4 squared plus 7 squared

Cos2(x-1) is equal to: 1/2 * (1 + Cos(2 - 2x)) (Cos(x) * Cos(1) - Sin(x) * Sin(1))2 1/4 * (2 + e2i - 2ix + e2ix - 2i) where e is the natural log and i is the imaginary unit.

No. Sin of any angle is always less than or equal to 1.

cos(2x) = 1 - 2(sin(x)^2), so sin(x)^2 = 1/2 - 1/2*cos(2x).

sinx(1-sinx)=0 sinx=0 or 1 x= 0, 90, 180, 270, 360...

8 squared x 2 is equal to 128.

cos2x = cos2x - sin2x

4. -2 squared means -2 times -2, so it's 4.

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