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How do you solve right spherical triangle when A is equal to 54 degrees 30' B equals 124 degrees 10' and C equals 90 degrees.Find the sides?
Wiki User
∙ 14y ago
Apply Napier's rule
sin co-c= (tanco-A)(tanco-B)
cosc= 1/tanAtanB
c= cos-1(1/tanAtanB)
c=118.96 degrees
sin a= (cosco-A)(cosco-C)
a= sin-1(sinAsinC)
a=45.52
sinb= (tancoA)(tana)
b=sin-1 (tana/tanA)
b=46.37 or >>>180-46.37 = 133.63
FA= c=118.96 degrees
a= 45.52 degrees
b= 133.63 degrees
Wiki User
∙ 14y ago
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