You can use the arctangent or the reverse tangent to solve for x, which is denoted by arctan or tan^-1.
If tan [x] = 3, then arctan [3] = x. This applies to all trigonometric functions (ex. if sin [x] = 94, then arcsin [94] = x.
Punch that into your calculator and the answer will be:
arctan [3.0] = 71.565 (degrees)
arctan [3.0] = 1.249 (radians)
for solving this ..the first thing to do is substitute tanx=t^2 then x=tan inverse t^2 then solve the integral..
If you set a function equal to zero and solve for x, then you are finding where the function crosses the x-axis.
1 (sec x)(sin x /tan x = (1/cos x)(sin x)/tan x = (sin x/cos x)/tan x) = tan x/tan x = 1
sec x - cos x = (sin x)(tan x) 1/cos x - cos x = Cofunction Identity, sec x = 1/cos x. (1-cos^2 x)/cos x = Subtract the fractions. (sin^2 x)/cos x = Pythagorean Identity, 1-cos^2 x = sin^2 x. sin x (sin x)/(cos x) = Factor out sin x. (sin x)(tan x) = (sin x)(tan x) Cofunction Identity, (sin x)/(cos x) = tan x.
tan(-x) = -tan(x)
It is NOT equal. Try calculating tan x, and tan 6x, for a few values of "x", on your scientific calculator. Perhaps you are supposed to solve an equation, and see FOR WHAT values of "x" the two are equal?
tan x
2.5 x 30 = 25tenths x 30 = 75
To solve for tan x degree 90 you do a few things. First, if x equals 90, then this equals 1.5597 radian or 89.36 degrees. This is the easiest way to solve tan x degree 90.
Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1
sin(x) = tan(x) when x equal 0
Yes. Both expressions are the same.
How do you solve ln|tan(x)|=ln|sin(x)|-ln|cos(x)|? Well you start by........
Solve for x, where tan² x - 3 = 0. tan² x = 3; then, sec² x = tan² x + 1 = 4, sec x = ±2, and cos x = 1 /sec x = ±½. Now, we know that sin 30° = ½; whence cos 60° = ½. Therefore, if 0 ≤ x < 2π, then x = 60°, 120°, 240°, or 300°; or, in radians, x = ⅓π, ⅔π, 1⅓π, or 1⅔π.
5/8 = tan(x) x = tan-1(5/8) = tan-1(0.625) = 0.558599 + k*pi radians or 32.00538 + k*180 degrees where k is an integer
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
7cos(x)=3sin(x) 7=3[sin(x)/cos(x)] 7=3tan(x) 7/3=tan(x) x=66.8, 246.8