y = 3 x (times) 8.
x=4 y=x+3 y=4+3 y=7
x = 3 and y = 3 Form a simultaneous equation and solve by elimination.
If you already know that x = -3 and y = 5 what linear equations are you wanting to solve?
To me, this looks solved but of you want it in parametrics, y = -3 +2t (teR)
3y=ab. Divide by 3 to get y=ab/3
If you're solving for x, then x = 3/y.
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
You need more information to solve for x and y. One answer is x=3 and y=1.
add 2 y to each side, divide by 3 and you get- y = x over 3
The given equation y=3+x is a linear line with the slope of 1 and y-intercept of 3.
Set x=0, solve for y, which is the y intercept: 0 - 3y = 9 --> y = -3. Set y=0 and solve for x = 9 for x-intercept.
a = 3 and y = 0
-3+y=17+1 im assuming solve for y?-3+y=18 add 3 to both sidesy=21
-y + y equals 0.
Y equals 1 and X equals 1
cross multiply 3/6=y/10 30=6y y=5
y/x is a constant; so first of you can solve for this constant. y/x=6/-3, or y/x=-2 y/4=-2 y=-8
To solve the equation you need to know at least a value for x or y. For example if x = 2 then the solution will show that y = 1.