To count the number of ions in a equation you will use a net ionic equation. To start with a net ionic equation start with a balanced equation, and break all soluble strong electrolytes.
You need to know the concentration of ions in the solution and the mass of this ion.
concentration/ionic mass = number of moles
watch jimmy nuetron
Only if you know how many moles there are.
The equation is: H2O------>H+ + OH-
Ions that appear on both sides of the equation are spectator ions. These ions do not participate in the reaction at all. Thus, they are omitted when writing the net ionic formula of a reaction.
The spectator ions in this precipitation equation are K+ and NO3-. The non-spectator ions are Pb2+ and I-. They combine to form the precipitate PbI2.
do you have another chemical equation with this as the answer could be 2CH30 my advice is to count the number of atoms and make sure they match if they do it is a balenced equation. If you have to write one yourself then make sure the numbers match.
Only if you know how many moles there are.
Carry out all the multiplications and divisions and then count them.
The total ionic equation shows all of the equation, even the spectator ions. The net ionic equation shows the net change after spectator ions have been removed.
To balance the number of sulfate ions on each side of the equation, a coefficient of 3 should be placed in front of CaSO4. This will give a total of 3 sulfate ions on each side of the equation.
The equation is: H2O------>H+ + OH-
The equation is: H2O------>H+ + OH-
You generally count them in moles, which is actually a number: 6.02X1023.
Ions that appear on both sides of the equation are spectator ions. These ions do not participate in the reaction at all. Thus, they are omitted when writing the net ionic formula of a reaction.
An equation showing all dissolved compounds as ions
the spectator ions are removed
the spectator ions are removed
In solution the number of chloride ions (negative) equals the number of positive ions (sodium). NaCl -> Na+ + Cl- which is neutral in totality (neither acid nor alkaline)