These ions are Pb(2+) and I-.
The spectator ions in this precipitation equation are K+ and NO3-. The non-spectator ions are Pb2+ and I-. They combine to form the precipitate PbI2.
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
K2CO3 + Sr(NO3)2 = SrCO3 + 2KNO3
Potassium Nitrite
Potassium chloride and magnesium nitrate doesn't react.
K2CO3 + 2HNO3 = 2KNO3 (potassium nitrate) + H2O + CO2 and it's nitric acid
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3 is a precipitation reaction. The PbI2 is insoluble in water and will precipitate. It is NOT neutralization, because you do not have an acid reacting with a base.
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
A precipitation reaction occurs. Yellow precipitates of lead iodide are formed. The equation for this reaction is Pb(NO3)2 + 2KI -----> PbI2 + 2KNO3
Pb(No3)2(aq) + KI(aq) --> PbI2(s) + KNO3(aq) aq = aqueous s = solid Lead iodide is a yellow precipitate!
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3
Pb(NO3)2 + 2KCl ---> PbCl2 + 2KNO3
2KNO3 (s) ==heat==> 2KNO2(s) + O2(g) potassium nitrate decomposes to potassium nitrite and oxygen. NB Note the spelling for the product.
2KOH + Ba(NO3)2 -----> 2KNO3 + Ba(OH)2
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
Potassium iodide and lead nitrate produces golden yellow precipitate of lead iodide and potassium nitrate. This reaction is a double displacement reaction and also it can be called a precipitation reaction as lead iodide gets precipitated. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
K2CO3 + Sr(NO3)2 = SrCO3 + 2KNO3
Do you mean chemical equation? 2AgNO3(aq) + K2SO4(aq) --> 2KNO3(aq) + Ag2SO4(s) This is an example of a double replacement/displacement reaction.