Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3
The balanced chemical equation for the reaction between lead (II) nitrate (Pb(NO3)2) and potassium iodide (KI) is: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3 This equation is already balanced as it has the same number of atoms of each element on both sides of the reaction arrow.
Equation: Pb(NO3)2 + KI ----> PbI2 + KNO3
The net ionic equation for the reaction between Pb(NO3)2 and KI is: Pb2+ (aq) + 2I- (aq) -> PbI2 (s) This represents the formation of solid lead(II) iodide.
When Pb(NO3)2 (lead nitrate) is mixed with KI (potassium iodide), a yellow precipitate of lead iodide (PbI2) is formed. This reaction can be represented by the equation: Pb(NO3)2 + 2KI -> 2KNO3 + PbI2.
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
The balanced chemical equation for the reaction between lead (II) nitrate (Pb(NO3)2) and potassium iodide (KI) is: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3 This equation is already balanced as it has the same number of atoms of each element on both sides of the reaction arrow.
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Equation: Pb(NO3)2 + KI ----> PbI2 + KNO3
The net ionic equation for the reaction between Pb(NO3)2 and KI is: Pb2+ (aq) + 2I- (aq) -> PbI2 (s) This represents the formation of solid lead(II) iodide.
When Pb(NO3)2 (lead nitrate) is mixed with KI (potassium iodide), a yellow precipitate of lead iodide (PbI2) is formed. This reaction can be represented by the equation: Pb(NO3)2 + 2KI -> 2KNO3 + PbI2.
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
The dissociation equation for Pb(NO3)2 in water is: Pb(NO3)2(s) → Pb2+(aq) + 2NO3-(aq)
Pb(NO3)2
The chemical equation for the reaction between lead nitrate (Pb(NO3)2) and potassium iodide (KI) to form lead iodide (PbI2) and potassium nitrate (KNO3) is: Pb(NO3)2 + 2KI → 2KNO3 + PbI2
Potassium Iodide- KI Lead Nitrate- Pb(NO3)2
The chemical equation is:2 KI + Pb(NO3)2 = 2 KNO3 + PbI2(s)