The chemical equation is:
2 KI + Pb(NO3)2 = 2 KNO3 + PbI2(s)
Yes, potassium phosphate is water soluble. It dissolves readily in water, forming an aqueous solution.
The balanced chemical equation for this reaction is CuNO3(aq) + K2S(aq) -> Cu2S(s) + 2KNO3(aq). When aqueous solutions of copper(1) nitrate and potassium sulfide are mixed, a double replacement reaction occurs, forming insoluble copper(1) sulfide precipitate. This is a precipitation reaction where the insoluble product is separated from the solution.
KOH(aq) + HNO3(aq) -> KNO3(aq) + H2O(l) This balanced ionic equation represents the neutralization reaction between potassium hydroxide (KOH) solution and nitric acid (HNO3), forming potassium nitrate (KNO3) and water (H2O).
Potassium ions (K+) are soluble in water due to their low charge density and small size, which allows them to interact more weakly with water molecules. This results in the dissociation of potassium compounds into their constituent ions without forming a precipitate in aqueous solutions.
This equation is: 2CH3COOH + Na2CO3 --> 2NaCH3COO + CO2 + H2O .
Yes, potassium phosphate is water soluble. It dissolves readily in water, forming an aqueous solution.
The balanced chemical equation for this reaction is CuNO3(aq) + K2S(aq) -> Cu2S(s) + 2KNO3(aq). When aqueous solutions of copper(1) nitrate and potassium sulfide are mixed, a double replacement reaction occurs, forming insoluble copper(1) sulfide precipitate. This is a precipitation reaction where the insoluble product is separated from the solution.
KOH(aq) + HNO3(aq) -> KNO3(aq) + H2O(l) This balanced ionic equation represents the neutralization reaction between potassium hydroxide (KOH) solution and nitric acid (HNO3), forming potassium nitrate (KNO3) and water (H2O).
Yes, MgCl2 can form an aqueous solution when it is dissolved in water. MgCl2 dissociates into magnesium (Mg2+) ions and chloride (Cl-) ions in water, forming an aqueous solution.
Potassium ions (K+) are soluble in water due to their low charge density and small size, which allows them to interact more weakly with water molecules. This results in the dissociation of potassium compounds into their constituent ions without forming a precipitate in aqueous solutions.
This equation is: 2CH3COOH + Na2CO3 --> 2NaCH3COO + CO2 + H2O .
Yes, a reaction will occur between niobium sulfate and barium nitrate in an aqueous solution, forming a precipitate of barium niobate. This compound is insoluble in water and will settle out of the solution.
When potassium iodide is added to a solution of bromine, a reaction occurs forming potassium bromide and iodine. The iodine produced in the reaction is responsible for the color change in the solution from orange to brown/black.
Potassium iodide is used in the preparation of iodine solution to increase the solubility of iodine in water. It helps stabilize the iodine in solution by forming triiodide ions, which prevents iodine from sublimating back to a solid state. Additionally, potassium iodide helps to maintain a consistent concentration of iodine in the solution.
True. In an aqueous solution of ionic compounds, the positive and negative ions will attract each other due to their opposite charges, forming electrostatic bonds known as dipole attractions.
When potassium metal (K) is added to a solution of barium acetate (Ba(C₂H₃O₂)₂), a single displacement reaction occurs. The balanced formula equation for this reaction is: [ 2 \text{K} + \text{Ba(C}_2\text{H}_3\text{O}_2\text{)}_2 \rightarrow \text{Ba} + 2 \text{KC}_2\text{H}_3\text{O}_2. ] In this reaction, potassium displaces barium, forming barium metal and potassium acetate.
The reaction between aqueous chlorine and sodium bromide solution results in the displacement of bromine by chlorine, forming sodium chloride and bromine gas as products. This is a redox reaction where chlorine is reduced and bromine is oxidized.