No reaction.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
Pb2+ + I- --> PbI2(s)potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
The solid formed when adding lead nitrate and potassium iodide and filtering the mixture is lead iodide. Lead iodide is a yellow precipitate that forms by the reaction between lead nitrate and potassium iodide.
A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.
When solutions of lead nitrate and potassium iodide are mixed, a yellow precipitate of lead iodide is formed. This reaction is a double displacement reaction where the lead from lead nitrate reacts with the iodide from potassium iodide to form the insoluble lead iodide.
lead nitrate(Pb(NO3)2 + potassium iodide(KI) = lead iodide(PbI) + potassium nitrate (KNO3)
The word equation for the reaction between potassium and iodine is: potassium + iodine → potassium iodide.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
Pb2+ + I- --> PbI2(s)potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)
A precipitate of Lead iodide and Potassium nitrate are formed
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Equation: Pb(NO3)2 + KI ----> PbI2 + KNO3
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
The reaction that occurs is a double displacement reaction where lead(II) nitrate and potassium iodide switch partners to form solid lead(II) iodide and potassium nitrate solution. This reaction can be represented by the equation Pb(NO3)2 + 2KI -> Pbl2 + 2KNO3.
The solid formed when adding lead nitrate and potassium iodide and filtering the mixture is lead iodide. Lead iodide is a yellow precipitate that forms by the reaction between lead nitrate and potassium iodide.