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What happens when you mix solutions of lead nitrate and potassium iodide?

When solutions of lead nitrate and potassium iodide are mixed, a yellow precipitate of lead iodide is formed. This reaction is a double displacement reaction where the lead from lead nitrate reacts with the iodide from potassium iodide to form the insoluble lead iodide.


What is the chemical formula for lead nitrate and potassium iodide reaction?

lead nitrate(Pb(NO3)2 + potassium iodide(KI) = lead iodide(PbI) + potassium nitrate (KNO3)


What is the word equation when potassium reacts with iodine?

The word equation for the reaction between potassium and iodine is: potassium + iodine → potassium iodide.


What would the balanced equation be for potassium iodide and lead II nitrates to produce potassium nitrate and lead iodidine?

The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.


What is the precipitate of lead nitrate and potassium iodide?

In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.


What is the word equation for the reaction bromine and potassium iodide?

Bromine and Potassium iodide react to form Potassium bromide and Iodine.


What is the balanced equation for lead acetate and potassium iodide producing potassium acetate and lead iodide?

Pb2+ + I- --> PbI2(s)potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)


Lead nitrate is treated with potassium iodide solution?

A precipitate of Lead iodide and Potassium nitrate are formed


What is the chemical formula for lead nitrate and potassium iodide?

Equation: Pb(NO3)2 + KI ----> PbI2 + KNO3


What happens when potassium iodide react with lead nitrate?

When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.


What are the reactants in this equation K2SO4 plus Pbl2 PbSO4 plus 2Kl?

The reactants in the equation are potassium sulfate (K₂SO₄) and lead(II) iodide (PbI₂). These substances react to form lead(II) sulfate (PbSO₄) and potassium iodide (KI) as products.


When lead(II) nitrate solution is added to potassium iodide solution solid lead(II) iodide forms and potassium nitrate solution remains.?

The reaction that occurs is a double displacement reaction where lead(II) nitrate and potassium iodide switch partners to form solid lead(II) iodide and potassium nitrate solution. This reaction can be represented by the equation Pb(NO3)2 + 2KI -> Pbl2 + 2KNO3.