In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
2KI+Pb(NO(3))(2) yields 2KNO(3)+PbI(2). You basically get potassium nitrate and lead (II) iodide when you react potassium iodide and lead nitrate dissolved in solution.
Produces yellow Lead(II) iodide and Sodium nitrate
Pb(NO3)2 + 2NaI = PbI2 = 2NaNO3 Lead iodide is a yellow precipitate.
Lead iodide (Pb2I) precipitates as a yellow solid, leaving a solution of potassium and nitrate ions.
Potassium iodide and lead nitrate produces golden yellow precipitate of lead iodide and potassium nitrate. This reaction is a double displacement reaction and also it can be called a precipitation reaction as lead iodide gets precipitated. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
A precipitate of Lead iodide and Potassium nitrate are formed
A yellow Lead(II) iodide precipitate
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
just a clorine hydroxyde :))
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
Lead iodide.
It produces Potassium nitrate and Lead iodide
Yellow; the insoluble precipitate Lead(II) iodide is created
A precipitate of yellow Lead iodide and Sodium nitrate are formed
potassium nitrate (aq) and lead iodide (s) are formed to create a yellow cloudy substance in a yellow liquid that will settle as a powder.
2KI+Pb(NO(3))(2) yields 2KNO(3)+PbI(2). You basically get potassium nitrate and lead (II) iodide when you react potassium iodide and lead nitrate dissolved in solution.
The chemical reaction is:Pb(NO3) 2 + 2 KI = PbI2(s) + 2 KNO3Lead iodide is insoluble in water and form an yellow precipitate.