Produces yellow Lead(II) iodide and Sodium nitrate
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
Sodium iodide and lead nitrate react to form sodium nitrate and lead iodide. This is a double displacement reaction where the positive ions in the two compounds switch places. Lead iodide is insoluble and will precipitate out of the solution.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
When potassium iodide is added to lead nitrate, a precipitation reaction occurs resulting in the formation of lead iodide, a yellow insoluble solid, and potassium nitrate, which remains in solution. This reaction can be visually identified by the formation of a yellow precipitate.
Lead iodide is prepared from lead nitrate because lead nitrate contains lead ions and nitrate ions that can react with iodide ions to form lead iodide. This reaction allows for the precipitation of lead iodide, which can then be isolated and collected.
The correct formula for the product of lead(II) nitrate reacting with sodium iodide is lead(II) iodide, which has the formula PbI2. This is because lead(II) ions from lead(II) nitrate react with iodide ions from sodium iodide to form lead(II) iodide as the product.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
The filtrate of lead nitrate and sodium iodide would contain soluble sodium nitrate and insoluble lead iodide. Lead iodide is a yellow solid that precipitates out of the solution, while sodium nitrate remains in the filtrate as it is soluble in water.
The formula for lead iodide is PbI2 and the formula for sodium nitrate is NaNO3.
Lead(II) nitrate and sodium iodide will yield lead(II) iodide and sodium nitrate. This is a double displacement reaction, where the cations and anions switch partners resulting in the formation of two new compounds.
When lead nitrate is mixed with sodium iodide, a solid precipitate of lead iodide is formed along with sodium nitrate. This reaction is a double displacement reaction where the cations of the two compounds switch partners to form the products. Lead iodide is a yellow precipitate that can be easily observed in the reaction mixture.
Sodium iodide and lead nitrate react to form sodium nitrate and lead iodide. This is a double displacement reaction where the positive ions in the two compounds switch places. Lead iodide is insoluble and will precipitate out of the solution.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The reaction between lead(II) nitrate and sodium iodide is a double replacement reaction. The products of this reaction are lead(II) iodide and sodium nitrate, formed through the exchange of ions.
Nickel and zinc chloride: Nickel chloride and zinc Chlorine and sodium: Sodium chloride Potassium nitrate and lead iodide: Potassium iodide and lead nitrate
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.