Pb(NO3)2 + 2NaI = PbI2 = 2NaNO3
Lead iodide is a yellow precipitate.
Produces Lead(II) iodide and Potassium nitrate
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Pb(NO3)2 + 2KI ------> PbI2 + 2KNO3 is the overall reaction
The net ionic equation is
Pb2+ + 2I- --> PbI2
Products are Sodium nitrate and insoluble yellow Lead iodide
Pbl2
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
Potassium chloride and Iodine
Nothing happens.
3CuI2 + 2Fe(NO3)3
2KI + Cl2 = 2KCl + I2
Silver nitrate plus potassium iodide yields silver iodide plus potassium nitrate.
No, reaction
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
The reaction is the following:AgNO3 + KI = KNO3 = AgI(s)
AgNO3 + KI ----> AgI(ppts.) + KNO3
Technically, yes. Potassium nitrate is a potassium atom attached to the nitrate ion.
Potassium chloride and Iodine
Nothing happens.
2 KBr + BaI2 ----> 2 KI + BaBr2
lead nitrate and hydrogen
Potassium nitrite, not Potassium nitrate which is KNO3